Triangle A″B″C″ is formed using the translation (x + 2, y + 0) and the dilation by a scale factor of one half from the origin. Which equation explains the relationship between segment AB and segment A double prime B double prime?

A) segment a double prime b double prime = segment ab over 2

B) segment ab = segment a double prime b double prime over 2

C) segment ab over segment a double prime b double prime = one half

D) segment a double prime b double prime over segment ab = 2

Answer:

A) segment a double prime b double prime = segment ab over 2.

It can be rewritten as:

$A"B" = \frac{AB}{2}$

Step-by-step explanation:

Here, we are given triangle A″B″C which was formed using the translation (x + 2, y + 0) and the dilation by a scale factor of one half from the origin.

We know segment A"B" equals segment AB multiplied by the scale factor.

A"B" = AB * s.f.

Since we are given a scale factor of ½

Therefore,

$A"B" = AB * \frac{1}{2}$

$A"B" = \frac{AB}{2}$

The equation that explains the relationship between segment AB and segment A"B" is

$A"B" = \frac{AB}{2}$

Option A is correct

5 0

2 years ago

a rectangular lawn of sides 400m and 300m is surrounded by a path of width 3 m . find the area of path

DiKsa [7]

Answer:

2109 meter squared

Step-by-step explanation:

$Area \: of \: path \\ = (400+3)(300+3)-400 \times 300 \\ = 403 \times 303 - 120000 \\ = 122,109 - 120000 \\ = 2109 \: {m}^{2}$

8 0

3 years ago