Ask question

Ask question

All categories

3 years ago

6

If Y varies directly with X solve the following :

1 answer:

tresset_1 [31]3 years ago

4 0

Answer:

B) When Y = 90

X = 90 x -3

= -270

C) When X = -8

Y = 33.6(approx.)

D) When Y = 12.6

X = 12.6 x 3

= 37.8

Hope this helps!

You might be interested in

Mandy charges all of her customers by weight so she gets $5 per kilogram of corn cobs or $1.25 for an individual corn cob. If Ma

guapka [62]

Answer:

$5

Step-by-step explanation:

Because everyone want to be rich!

7 0

2 years ago

The coordinates of the vertices of □PQR are (-2,5), Q(-1,), and R(7,3). Determine whether □ PQR is a right triangle. Show Your W

alexdok [17]

Answer:

Slope of PQ

m

r

=

y

Q

−

y

P

x

Q

−

x

P

=

1

−

5

−

1

−

(

−

2

)

=

−

4

Slope of QR

m

p

=

y

R

−

y

Q

x

R

−

x

Q

=

3

−

1

7

−

(

−

1

)

=

1

4

Slope of RP

m

q

=

y

R

−

y

P

x

R

−

x

P

=

3

−

5

7

−

5

=

−

1

Since slopes PQ & PR,

m

r

=

−

1

m

p

, it's a right triangle

4 0

3 years ago

-4(x+1)-3=-3(x-4) solve for x please. Giving brainliest

Sophie [7]

Answer:

-19 = x

Step-by-step explanation:

Step 1: Write equation

-4(x + 1) - 3 = -3(x - 4)

Step 2: Solve for <em>x</em>

<u>Distribute:</u> -4x - 4 - 3 = -3x + 12

<u>Combine like terms:</u> -4x - 7 = -3x + 12

<u>Add 4x on both sides:</u> -7 = x + 12

<u>Subtract 12 on both sides:</u> -19 = x

4 0

3 years ago

Read 2 more answers

(x+7)^2+9=0<br><br> Find x with quadratics

Ne4ueva [31]

Answer:

x = -7 ±3i

Step-by-step explanation:

(x+7)^2+9=0

Subtract 9 from each side

(x+7)^2+9-9=0-9

(x+7)^2=-9

Take the square root of each side

sqrt((x+7)^2) = ±sqrt(-9)

We know sqrt(ab) = sqrt(a) sqrt(b)

x+7 = ±sqrt(-1) sqrt(9)

We know that sqrt(-1) is the imaginary number i

x+7 = ±i *3

x+7 =±3i

Subtract 7 from each side

x+7-7 = -7 ±3i

x = -7 ±3i

6 0

3 years ago

Read 2 more answers

X^2=4x-15 solve with Quadratic formula

bulgar [2K]

Answer:

$x=2+i\sqrt{11}$

$x=2-i\sqrt{11}$

Step-by-step explanation:

we have

$x^{2} =4x-15$ -------> $x^{2}-4x+15=0$

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2}-4x+15=0$

so

$a=1\\b=-4\\c=15$

substitute in the formula

$x=\frac{-(-4)(+/-)\sqrt{-4^{2}-4(1)(15)}} {2(1)}$

$x=\frac{4(+/-)\sqrt{16-60}} {2}$

Remember that

$i=\sqrt{-1}$

$x=\frac{4(+/-)\sqrt{-44}} {2}$

$x=\frac{4(+/-)2i\sqrt{11}} {2}$

$x=\frac{4(+)2i\sqrt{11}}{2}=2+i\sqrt{11}$

$x=\frac{4(-)2i\sqrt{11}}{2}=2-i\sqrt{11}$

7 0

3 years ago