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Gnom [1K]
4 years ago
6

If Y varies directly with X solve the following :

Mathematics
1 answer:
tresset_1 [31]4 years ago
4 0

Answer:

B) When Y = 90

X = 90 x -3

= -270

C) When X = -8

Y = 33.6(approx.)

D) When Y = 12.6

X = 12.6 x 3

= 37.8

Hope this helps!

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Help the question is the picture
nikdorinn [45]

Answer:

a>-21(1/3)

Step-by-step explanation:

3/4a>-16

first thing is to divide both sides by 3/4 to isolate the variable.

Since it is not negative, the sign stays the same.  

-16/0.75=-21.3 repeating or just 1/3

5 0
3 years ago
Prime factoring | Example answer: 12=2x2x3 if it is prime, use the factors 1 and itself, example: 13=1x13
Anna007 [38]
32 = 2x2x2x2x2

99 = 11x3x3

100 = 5x5x2x2

400 = 2x2x2x2x5x5

39 = 3x13

35 = 5x7

80 = 2x2x2x2x5

42 = 2x3x7

5 = 1x5

78 = 2x3x13
6 0
3 years ago
Alex Bought 10 smoothies he gave 3/5 of the smoothies to his friends and the rest of his family how many smoothies did he give t
Semenov [28]
He gave his friends 6 smoothies bc if u multiply 3/5 by 2 it is 6/10 and 10-6=4 so his family got 4 smoothies.
7 0
3 years ago
6c - 8 - 2c - 16<br> What is the solution
UkoKoshka [18]

Answer:

4 (c - 6)

Step-by-step explanation:

Simplify the following:

6 c - 2 c - 16 - 8

Hint: | Group like terms in 6 c - 2 c - 16 - 8.

Grouping like terms, 6 c - 2 c - 16 - 8 = (6 c - 2 c) + (-8 - 16):

(6 c - 2 c) + (-8 - 16)

Hint: | Combine like terms in 6 c - 2 c.

6 c - 2 c = 4 c:

4 c + (-8 - 16)

Hint: | Evaluate -8 - 16.

-8 - 16 = -24:

4 c + -24

Hint: | Factor out the greatest common divisor of the coefficients of 4 c - 24.

Factor 4 out of 4 c - 24:

Answer: 4 (c - 6)

7 0
3 years ago
What is the area of the figure?<br><br>a 28 yd<br><br>b 40 yd<br><br>c 52 yd<br><br>d 64 yd
Vilka [71]

Answer:

<h2>b. 40 yd²</h2>

Step-by-step explanation:

We have the square and the right triangle.

The formula of an area of a square:

A_{\boxed{}}=a^2

a - length of side

The formula of an area of a right triangle:

A_\triangle=\dfrac{ab}{2}

a,b - legs

We have:

SQUARE:

a = 4 yd

A_{\boxed{}}=4^2=16\ yd^2

RIGHT TRIANGLE:

a = 6 yd, b = 4 yd + 4 yd = 8 yd

A_\triangle=\dfrac{(6)(8)}{2}=(3)(8)=24\ yd^2

The area of the figure:

A=A_{\boxed{}}+A_\triangle\\\\A=16\ yd^2+24\ yd^2=40\ yd^2

8 0
3 years ago
Read 2 more answers
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