All categories

3 years ago

Which statements are true? Check all that apply. ( the formula for the area of a triangle is A = 1/2bh.)

Mathematics

1 answer:

never [62]3 years ago

5 0

The formula is correct but I do not see any of the other statements. so yes the formula is true.

You might be interested in

A rectangle has an area of 10x^2-29x-21 square units. Which of the following could represent the primeter of the rectangle in te

nata0808 [166]

Area=LW
<span>10x^2-29x-21=area
factor and those are the lengh and width
(2x-7)(5x+3)
perimiter=2(L+W)
P=2(2x-7+5x+3)
P=2(7x-4)
P=14x-8

answer is D
</span>

5 0

3 years ago

PLEASE HELP!!!!!!!! Just all of 2 and 4 PLEASE

alukav5142 [94]

Answer: question 2 b = $3.5992

question 2 c = $48.5892 or you can write $48.58

thats how much i know i dont know about the rest sorry

i will try them out and come back to you if i find an answer

Step-by-step explanation:

6 0

3 years ago

Find the area of the circle with the given radius or diameter. Use 3.14.

elena55 [62]

Answer:

Step-by-step explanation:

If the radius, r, is given, then the area of the circle is A = πr².

If the diameter, d, is given, then the circle area is A = π(d/2)², or A = πd² / 4.

4 0

2 years ago

Mathswatch Question! Mr Powers checks his electricity bill. Here are his meter readings. New reading: 6538 units, Old reading: 6

Setler79 [48]

Answer:

$Cost = 284 x$

Step-by-step explanation:

Given

$Old = 6245\ units$

$New = 6538\ units$

Required

The cost of units used

First, calculate the number of units used.

$Units = New - Old$

$Units = 6538 - 6254$

$Units = 284$

Next, multiply the units used by the cost per units,

Since the cost per unit is not given, we assume that it is x.

So, the total cost is:

$Cost = Units * Cost\ per\ units$

$Cost = 284 * x$

$Cost = 284 x$

3 0

3 years ago

Given sin theta= 6/11 and sec theta < 0, find cos theta and tan theta.

bekas [8.4K]

Answer: option a.

Step-by-step explanation:

By definition, we know that:

$cos^2(\theta)=1-sen^2(\theta)\\\\tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

Substitute $sin(\theta)=\frac{6}{11}$ into the first equation, solve for the cosine and simplify. Then, you obtain:

$cos(\theta)=\±\sqrt{1-(\frac{6}{11})^2}\\\\cos(\theta)=\±\sqrt{\frac{85}{121}}\\\\ cos(\theta)=\±\frac{\sqrt{85}}{11}$

As $sec\theta$ then $cos\theta$ :

$cos(\theta)=-\frac{\sqrt{85}}{11}$

Now we can find $tan\theta$ :

$tan\theta=\frac{\frac{6}{11}}{-\frac{\sqrt{85}}{11}}\\\\tan\theta=-\frac{6\sqrt{85}}{85}$

4 0

3 years ago

Read 2 more answers