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Talja [164]
3 years ago
12

Type the correct answer in each box.

Mathematics
2 answers:
Harman [31]3 years ago
6 0

Answer:

X=-1/2

Y=3/4

Step-by-step explanation:

777dan777 [17]3 years ago
6 0

multiply second equation by 2

48x-8y=-30

add with first equation

50x=-25

divide by 50

x=-½

substitute to first equation

2(-½)+8y=5

-1+8y=5

8y=6

y=¾

hence the solution to the system is (-½,¾)

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Rom4ik [11]

Answer:

Step-by-step explanation:

(5,7) and (7,-3)

m=(-3-7)/(7-5) = -10/2 = -5

Equation of a line is

y-y1 =m(x-x1)

y-6 = -5(x-5)

y = -5x +25+6

y = -5x +31

7 0
3 years ago
Write the justifications for the following line transitions.
Lera25 [3.4K]

Hi

Here is the Justification

Line 1 : 3p-(p+8) = 5p-7            [Given]

Line 2:  3p-p-8=5p-7               [ Applying distributive property]

Line 3:  2p-8=5p-7                   [Simplifying like terms]

Line 4:   -8=3p-7                       [Subtraction property]

Line 5 -1=3p                              [Additive property](Add 7 on both sides]

Line 6 -1/3=p                             [Multiplicative inverse or division]

Line 7 p=-1/3                             [Property of equality]


Thank you.

5 0
3 years ago
Check the true statements below:
valentinak56 [21]

Answer:

a) False

b) False

c) True

d) False

e) False

Step-by-step explanation:

a. A single vector by itself is linearly dependent. False

If v = 0 then the only scalar c such that cv = 0 is c = 0. Hence, 1vl is linearly independent. A set consisting of a single vector v is linearly dependent if and only if v = 0. Therefore, only a single zero vector is linearly dependent, while any set consisting of a single nonzero vector is linearly independent.

b. If H= Span{b1,....bp}, then {b1,...bp} is a basis for H. False

A sets forms a basis for vector space, only if it is linearly independent and spans the space. The fact that it is a spanning set alone is not sufficient enough to form a basis.

c. The columns of an invertible n × n matrix form a basis for Rⁿ. True

If a matrix is invertible, then its columns are linearly independent and every row has a pivot element. The columns, can therefore, form a basis for Rⁿ.

d.  In some cases, the linear dependence relations among the columns of a matrix can be affected by certain elementary row operations on the matrix. False

Row operations can not affect linear dependence among the columns of a matrix.

e. A basis is a spanning set that is as large as possible. False

A basis is not a large spanning set. A basis is the smallest spanning set.

3 0
3 years ago
−2&gt;m/6−7<br><br>can you please show your work<br><br>Thx!!
Aleksandr [31]
I do believe the answer is m<30
4 0
3 years ago
please help!!!! 10 points!!!!! I’ve been trying to figure this out for 45 mins now and still haven’t been able to :(
7nadin3 [17]
What does this mean I’m confused
7 0
3 years ago
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