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vampirchik [111]
3 years ago
13

if a + b + c is equals to 270 then prove that sin a cos b sin c + cos a sin b sin c + sin a sin b cos c = cos a cos b cos c​

Mathematics
1 answer:
4vir4ik [10]3 years ago
4 0

Answer:

Solution,\\a +b+c=270\\or, a +b = 270-c\\

cos(a+b) = cos(270-c)~~~~~~~~~and~~~~~~~~~sin(a+b)=sin(270-c)\\or, cos(a+b) = -sinc,~sin(a+b) = -cosc\\Now,\\L.H.S. = sina.cosb.sinc +cosa.sinb.sinc + sina.sinb.cosc\\~~~~~~~~~~= sinc (sina.cosb+cosa.sinb)+sina.sinb.cosc\\~~~~~~~~~~=sinc[sin(a+b)]+sina.sinb.cosc\\~~~~~~~~~~=sinc.-cosc+sina.sinb.cosc\\~~~~~~~~~~=cosc(sina.sinb-sinc)\\~~~~~~~~~~=cosc[sina.sinb+cos(a+b)]\\~~~~~~~~~~=cosc[sina.sinb+cosa.cosb-sina.sinb]\\~~~~~~~~~~=cosc.cosa.cosb\\~~~~~~~~~~=cosa.cosb.cosc \\

Hope I helped you!

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The formula for finding area is l × w

If the area is 19 ½ inches and it was 3 ¼ inches wide, then the length will be 19 ½ ÷ 3 ¼ (Area ÷ Width)

19  \frac{1}{2} \div 3  \frac{1}{4}

Change both to improper fraction

19  \frac{1}{2} =   \frac{39}{2}

3  \frac{1}{4} =  \frac{13}{4}

\frac{39}{2} \div  \frac{13}{4}

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Change ÷ to ×
Flip 13/4 = 4/13

\frac{39}{2} \times  \frac{4}{13} =  \frac{156}{26} = 6

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