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2 years ago

9

Suppose that Y and Z are points on the number line.

1 answer:

uranmaximum [27]2 years ago

4 0

9514 1404 393

Answer:

-3, 13

Step-by-step explanation:

8 units to the left of 5 on the number line is 5-8 = -3.

8 units to the right of 5 on the number line is 5+8 = 13.

The possible locations of Y are -3 or 13.

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PLEASE HELP ME!!! I need to simplify these equations, not answer them.

Leya [2.2K]

Answer:

Step-by-step explanation:

a= 2qr^3 quotent 6p^2

8 0

3 years ago

In triangle ABC the measure of A is 33° and the measure of C is 90° . what is the measure of B

Masteriza [31]

Answer:

57°

Step-by-step explanation:

ALL angles in a triangle add up to 180°

SO, if we know the sum of two angles which is 123° (why: 33+90=123), all we have to do is subtract this number from 180 to get the measure of the 3rd angle. Which in this case is 57°

6 0

2 years ago

Below are survival times (in days) of 13 guinea pigs that were injected with a bacterial infection in a medical study:

tresset_1 [31]

Outliers are data that are relatively far from other data elements.

The dataset has an outlier and the outlier is 120

The dataset is given as:

91 83 84 79 91 93 95 97 97 120 101 105 98

Sort the dataset in ascending order

79 83 84 91 91 93 95 97 97 98 101 105 120

<h3>The lower quartile (Q1)</h3>

The Q1 is then calculated as:

$Q1 = \frac{N +1}{4}th$

So, we have:

$Q1 = \frac{13 +1}{4}th$

$Q1 = \frac{14}{4}th$

$Q1 = 3.5th$

This is the average of the 3rd and the 4th element

$Q1 = \frac{1}{2} \times (84 + 91)$

$Q1 = 87.5$

<h3>The upper quartile (Q3)</h3>

The Q3 is then calculated as:

$Q3 = 3 \times \frac{N +1}{4}th$

So, we have:

$Q3 = 3 \times \frac{13 +1}{4}th$

$Q3 = 3 \times 3.5th$

$Q3 = 10.5th$

This is the average of the 10th and the 11th element.

$Q_3 =\frac12 \times (98 + 101)$

$Q_3 =99.5$

<h3>The interquartile range (IQR)</h3>

The IQR is then calculated as:

$IQR = Q_3 -Q_1$

$IQR = 99.5 - 87.5$

$IQR = 12$

Also, we have:

$IQR(1.5) = 12 \times 1.5$

$IQR(1.5) = 18$

<h3>The outlier range</h3>

The lower and the upper outlier range are calculated as follows:

$Lower = Q_1 - IQR(1.5)$

$Lower = 87.5- 18$

$Lower = 69.5$

$Upper = Q_3 + IQR(1.5)$

$Upper = 99.5 + 18$

$Upper = 117.5$

120 is greater than 117.5.

Hence, the dataset has an outlier and the outlier is 120

Read more about outliers at:

brainly.com/question/9933184

6 0

2 years ago

Simplify 6(501) using the distributive property. 3012 3006 2988 3000

ella [17]

Ok so, I assume this is 6 times 501
   501
   x 6
-------------
   3006

5 x 6 = 30
6 x 0 = 0
6 x 1 = 6

3 0

3 years ago

Read 2 more answers

zubka84 [21]

————————————-The answer is 3.78

6 0

2 years ago

Read 2 more answers