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Fittoniya [83]
3 years ago
7

Will the square roots of perfect squares always be irrational numbers

Mathematics
2 answers:
pshichka [43]3 years ago
8 0

Answer:

no

Step-by-step explanation:

because it's not amig9

Reil [10]3 years ago
3 0
Nope

hopefully this helped !!
You might be interested in
A person invests $4000 at 2% interest compounded annually for 4 years and then invests the balance (the $4000 plus the interest
faltersainse [42]
\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$4000\\
r=rate\to 2\%\to \frac{2}{100}\to &0.02\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &4
\end{cases}
\\\\\\
A=4000\left(1+\frac{0.02}{1}\right)^{1\cdot 4}\implies A=4000(1.02)^4\implies A\approx 4329.73

then she turns around and grabs those 4329.73 and put them in an account getting 8% APR I assume, so is annual compounding, for 7 years.

\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$4329.73\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &7
\end{cases}
\\\\\\
A=4329.73\left(1+\frac{0.08}{1}\right)^{1\cdot 7}\implies A=4329.73(1.08)^7\\\\\\ A\approx 7420.396

add both amounts, and that's her investment for the 11 years.
7 0
3 years ago
Need help on this problem
trasher [3.6K]
The answer to the question

3 0
3 years ago
Would the answer be 36?
umka2103 [35]

Answer:

No, it would be 72

Step-by-step explanation:

In similar triangles, the sides are different but the angles are the same. You still had a great guess though :)

Pls give brainliest

6 0
3 years ago
Which is greater number seven
zhuklara [117]
74% is greater than 11/15
6 0
3 years ago
Read 2 more answers
A matrix a is given. determine if the system ax = b (where x and b have the appropriate number of components) has a solution for
Alborosie
We can write the system in the following form:
\left[\begin{array}{cccc}5&-4&4&2\end{array}\right]  \left[\begin{array}{c}x_1\\x_2\\x_3\\x_4\end{array}\right]  =b
The above system is equivalent to the following equation:
5x_1-4x_2+4x_3+2x_4=b,\forall b\in\mathbb{R}
Of course, the above system has solution for any values of b since there is one equation and four variable, there is infinite number of solution each time. 
5 0
3 years ago
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