Answer:
<h2>There are 13 quarters, 5 nickels and 20 dimes.</h2>
Step-by-step explanation:
Givens
- Max has $5.50.
- He has eight more quarters than he does nickels.
- He had four times as many dimes as he has nickels.
From these statements, we can deduce algebraical expressions to solve the problem. Let's call 
quarters, 
nickels and 
dimes.
(8 more quarters than nickels)
(he has four times as many dimes as he has nickels).
(Max has a total of $5.50, one quartes is $0.25, one nickel is $0.05 and one dime is $0.10).
Let's replace the first two expressions into the third equation
There are 5 nickels.
Now, we use this value to find the number of quarters
There are 13 quarters.
Also, 
There are 20 dimes.
Therefore, there are 13 quarters, 5 nickels and 20 dimes.
Answer:
volume of a cube = 441cm3.
l³=441cm³
l=7.6cm
An arithmetic sequence starts with one number and you add the common difference to the previous term to get the current term
So...
f(x)=mx+b
m=common difference
b=starting point
f(11)=125=11m+b
-
f(1)=5=1m+b
--------
120=10m
Divide both sides by 10
12=m
Your common difference is 12.
Answer:
- the domain is [0,129]
- 112 mm
- 1942
Step-by-step explanation:
1. The function is good for years 1880 to 2009, 0 to 129 years after 1880. Values of x can be anything in the domain [0, 129].
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2. 1950 -1880 = 70. The year 1950 corresponds to x=70, so the function tells us the water level rose ...
f(70) = 1.6·70 = 112 . . . . . mm
__
3. We want to find x when f(x) = 100. That will be the solution to ...
100 = 1.6x
100/1.6 = x = 62.5
Then 62.5 years after 1880 is year 1942.5. The water level was 100 mm higher than in 1880 in the year 1942.
(-1,-4) this is saying that when x=-1, y=-4. Plugging it into the line equation y=4x gives
Which is correct.
