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3 years ago

Mechanical advantage what does this mean for a simple machine

1 answer:

7 0

Mechanical advantage is a measure of the force amplification achieved by using a tool, mechanical device or machine system. Ideally, the device preserves the input power and simply trades off forces against movement to obtain a desired amplification in the output force. The model for this is the law of the lever. Machine components designed to manage forces and movement in this way are called mechanisms. An ideal mechanism transmits power without adding to or subtracting from it. This means the ideal mechanism does not include a power source, and is frictionless and constructed from rigid bodies that do not deflect or wear. The performance of a real system relative to this ideal is expressed in terms of efficiency factors that take into account friction, deformation and wear.

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The boiling point of a substance is _72 degree Celsius. This temperature will be equivalent to Kelvin scale is-------.

Vlada [557]

Answer:

345 K

Explanation:

Temperature can be defined as a measure of the degree of coldness or hotness of a physical object.

Generally, it is measured with a thermometer and its units are Celsius (°C), Kelvin (K) and Fahrenheit (°F).

Given the following data;

Boiling point = 72°C

To convert the temperature in degree Celsius to Kelvin, we would use the following mathematical expression;

Kelvin = 273 + °C

Substituting into the formula, we have;

Kelvin = 273 + 72

Kelvin = 345 K

Therefore, the temperature of 72°C will be equivalent to 345 K on the Kelvin scale.

3 0

3 years ago

A piece of taffy slams into and sticks to another identical piece of taffy that is at rest. The momentum of the two pieces stuck

-Dominant- [34]

Answer:

C. 50%

Explanation:

Lets consider that the mass of taffy is m and its initial velocity is u and final velocity is v. Momentum is conserved so we can write it as,

$mu = 2mv\\v = \frac{u}{2} \\$

The initial kinetic energy = $\frac{mu^{2} }{2}$

As the Kinetic energy partly converted into heat.

The final kinetic energy = $\frac{m(\frac{u}{2})^{2} }{2}$ = $\frac{mu^{2} }{4}$

Change in the kinetic energy = $\frac{mu^{2} }{2} - \frac{mu^{2} }{4} = \frac{mu^{2} }{4}$

now we can determine the fraction of kinetic energy that has turned into heat

= $\frac{Heat energy}{initial K.E}$ = $\frac{\frac{mu^{2} }{4} }{\frac{mu^{2} }{2} } = 1/2$

= 50%

3 0

4 years ago

an astronaut weighs 8.00x10^2 on the surface of earth. what is the weight of the astronaut 6.37x10^6 meters above the surface of

Marta_Voda [28]

To solve this problem, we use the Law of Universal Gravitation:

F = Gm1m2/d^2

where m1 and m2 are two objects. In this case, earth and man. d is the distance between the objects. Lastly, G is the gravitational constant. Since the mass of the earth and man are constant, this is lumped up with G into k. The equation would be:

F = k/d^2
k = Fd^2
$F_{1} d_{1} ^{2} =F_{2} d_{2} ^{2}$

The radius of earth, d1, is equal to 6.371E+6 m. Thus, d2 = 2d1

(8E+2)(d1)^2 = F2(2d1)^2

(8E+2)(d1)^2 = 4F2(d1)^2

(8E+2)=4F2
F2 = 200 Newtons

4 0

3 years ago

Una grúa está subiendo una caja de 1000 kg atada a una cadena. La caja, que inicialmente está en reposo, incrementa su velocidad

BabaBlast [244]

Answer:

40 metros en 10 segundos.

Explicación:

Una grúa está levantando una caja de 1000 kg atada a una cadena y la caja, que inicialmente está en reposo, aumenta su velocidad en 4 m / s por segundo, por lo que si la región de colocación está a 40 metros de distancia, la grúa tarda 10 segundos en completar el proceso. tarea de movimiento y colocación de la caja. La grúa se utiliza para levantar y mover cargas pesadas, máquinas, materiales y mercancías para diferentes propósitos. Entonces el trabajo realizado por la grúa depende de la velocidad y la distancia de colocación.

3 0

3 years ago

The matter that makes up a planet is distributed uniformly so that the planet has a fixed, uniform density. How does the magnitu

Trava [24]

Answer:

the acceleration due to gravity g at the surface is proportional to the planet radius R (g ∝ R)

Explanation:

according to newton's law of universal gravitation ( we will neglect relativistic effects)

F= G*m*M/d² , G= constant , M= planet mass , m= mass of an object , d=distance between the object and the centre of mass of the planet

if we assume that the planet has a spherical shape, the object mass at the surface is at a distance d=R (radius) from the centre of mass and the planet volume is V=4/3πR³ ,

since M= ρ* V = ρ* 4/3πR³ , ρ= density

F = G*m*M/R² = G*m*ρ* 4/3πR³/R²= G*ρ* 4/3πR

from Newton's second law

F= m*g = G*ρ*m* 4/3πR

thus

g = G*ρ* 4/3π*R = (4/3π*G*ρ)*R

g ∝ R

8 0

3 years ago