Answer:
The rotor's angular velocity is 82.73rad/s
Explanation:
It is a curvilinear movement of a constant radius. If there is uniform angular acceleration, then it is a circular motion with constant acceleration, whose equations are analogous to that of the translational motion.
Calculating the initial velocity of the rotor, V1 in rad/s
V1 = 610rev/minute × 6.28 × 1miute/60secs
V1 = 63.85rad/s
Using kinematic equation to calculate the final velocity of the rotor
Given:
Angular acceleration = 5.9rad/s^2
Time,t= 3.2seconds
V2 = V1 + a × t
V2 = 63.85 + (5.9)× (3.2)
V2 = 63.85 + 18.88
V2 = 82.73rads/s
Answer:
18
Explanation:
The s-, p-, and d-block elements of the periodic table are arranged into 18 numbered columns, or groups.
Velocities of their center of mass after collisions are found by the following formula as shown in the image:
<h3>What are elastic collisions?</h3>
- An elastic collision is one in which there is no energy lost during the impact. A moderately inelastic collision occurs when some energy is wasted yet the items do not cling together. The maximum amount of energy is wasted when the objects collide in a perfectly inelastic impact. The kinetic energy doesn't change.
- It may be two dimensions or one dimension. Because there will always be some energy exchange, no matter how tiny, totally elastic collision is not conceivable in the real world.
- While the overall system's linear momentum does not change, the individual momenta of the participating components do, and because these changes are equal and opposite in size and cancel each other out, the initial energy is conserved.
To learn more about Elastic collisions refer to:
brainly.com/question/2356330
#SPJ4
Answer:
a) 8.58 m/s upward
b) -2.211 m/s downward
Explanation:
Let gravitational acceleration g = -9.81m/s2. This is negative because it deceleration the upward motion of the key.
(a)We have the following equation of motion

where
is the initial upward velocity of the keys, t = 1.1s is the time it takes for the keys to travel a distance of s = 3.5 m




So the keys were thrown initially upward with a speed of 8.58 m/s
(b) If the initial velocity of the key is 8.58 m/s and it is subjected to a deceleration of 9.81m/s2 for 1.1s then the velocity right at the 1.1s instant is

So they keys would have a downward speed of 2.211 m/s