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Aleksandr-060686 [28]
3 years ago
14

You are in a car and go around a corner very fast. What happens to you?

Physics
1 answer:
Fiesta28 [93]3 years ago
3 0

Answer:

You may tip the car over or crash.

Explanation:

Going really fast at high speeds and turn a corner might make the car crash into an object or fall over.

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You are asked to determine the density of a liquid. What lab equipment is most helpful to find density of the liquid?
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D. The graduated cylinder is used to find the volume, and triple beam balance is used to find the mass.
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Energy flows from the sun to _______ to consumers and eventually to _______
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the answer is c. producers, detrivores

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A proton, an electron, and a helium nucleus all move at speed v. Rank their de Broglie wavelengths from largest to smallest. Wri
MatroZZZ [7]

Answer:

The correct option is 'c':electron,proton,helium nucleus

Explanation:

The De-Broglie's wavelength of particle is given by

\lambda =\frac{h}{mv}

Thus we can see that wavelength is inversely related to mass of the particle since 'h' (Plank's constant) and velocity is same for all the particles  

Thus we conclude that the the lightest particle will have the most wavelength

Electron being the lightest of the 3 particles will have the largest wavelength thus the correct option is 'c'. Since electron has the largest wavelength followed by proton and the least wavelength among the 3 is of helium.

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3 years ago
Why can a hurricane cause so much destruction?
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Answer:

When a cyclone continues to be out over the ocean, the winds and huge waves that area unit created by the storm become dangerous for ships and alternative water vessels. ... once the cyclone approaches land it will cause an enormous quantity of injury. Flooding caused by storm surges is one among the foremost dangerous components of a cyclone.

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Which of the following metals require ultraviolet light to exhibit the photoelectric effect?The options available: a. Cs, work f
Eddi Din [679]

Answer:

b. AG, work function=4.74eV

Explanation:

Ultraviolet light starts at the end of the visible light spectrum, where violet light ends:

\lambda=380 nm =3.8\cdot 10^{-7}m (wavelength of lowest-energy ultraviolet light)

So, the lowest energy of ultraviolet light can be found by using the formula

E=\frac{hc}{\lambda}

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c is the speed of light

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E=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{3.8\cdot 10^{-7} m}=5.23\cdot 10^{-19}J

And keeping in mind that

1 eV = 1.6\cdot 10^{-19}J

This energy converted into electronvolts is

E=\frac{5.23\cdot 10^{-19} J}{1.6\cdot 10^{-19} J/eV}=3.27 eV

The work function of a metal is the minimum energy needed to extract a photoelectron from the surface of the metal. Therefore, the metals that exhibit photoelectric effect are the ones whose work function is larger than the energy we found previously, so:

b. AG, work function=4.74eV

Because for all the other metals, visible light will be enough to extract photoelectrons.

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