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xxMikexx [17]
3 years ago
10

If ∠A and ∠B are supplementary and ∠A = 4x – 8 and ∠B = 2x +2, what is the value of x?

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
7 0
Set them equal together. 4x-8=2x+2. Subtract 2x on both sides. 2x-8=2. Add 8 on both sides. 2x=10. Divide 2 on both sides x=5. Check answer!!!
4(5)-8=12
2(5)+2=12 
12=12
So answer is x=5!!!!
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