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3 years ago

If &angle;A and &angle;B are supplementary and &angle;A = 4x – 8 and &angle;B = 2x +2, what is the value of x?

1 answer:

7 0

Set them equal together. 4x-8=2x+2. Subtract 2x on both sides. 2x-8=2. Add 8 on both sides. 2x=10. Divide 2 on both sides x=5. Check answer!!!
4(5)-8=12
2(5)+2=12
12=12
So answer is x=5!!!!

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Help me with this problem please

Katena32 [7]

Answer:

$(a)\ A_1 = s^2$

$(b)\ A_2 = 4s^2$

Step-by-step explanation:

Given

Small Square:

$Dimension: s$

Large Square:

$Dimension: 2s$ i.e. twice as long as the small square

Solving (a): The area of the small square.

This is calculated as

$Area = Length^2$

So, we have:

$A_1 = s^2$

Solving (b): The area of the large square.

This is calculated as

$Area = Length^2$

So, we have:

$A_2 = (2s)^2$

$A_2 = 4s^2$

Solving (c): Number of small square to cover the large square

To do this, we simply divide their areas.

Let n represents the required number; n is calculated as:

$n = \frac{A_2}{A_1}$

$n = \frac{4s^2}{s^2}$

$n = 4$

Hence, 4 small squares is required to cover the large square

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