comparing the relation given
thus y= -2x +1 to the general equation of a line
where y= mx + c
where m is the gradient and c is the intercept on the y-axis.
from the question, the gradient is -2 and since the line is perpendicular, the gradient is given as
so substituting the value of m in to the equation
=
as the gradient
equation of line is given by
y - y1 = m( x-x1)
from the question y1= -2 and x1=1
substitute them
y-(-2) = 1/2 (x -1)
y+2 =1/2 (x-1)
multiplying through by 2
2 (y+2) = x-1
2y +4 = x-1
2y =x-1-4
2y =x-5
x -2y -5 = 0
therefore the equation for the line is x-2y -5=0
Answer:
Step-by-step explanation:
y = C(x - 1/3)(x - 1/3)(x + 1/4)
y = C(x² - 2/3x + 1/9)(x + 1/4)
y = C(x³ - 2/3x² + 1/4x² + 1/9x - 1/6x + 1/36)
y = C(x³ - 5/12x² - 1/18x + 1/36)
now to account for the y intercept (x = 0)
-3 = C((0)³ - 5/12(0)² - 1/18(0) + 1/36)
-3 = C(1/36)
C = -108
distribute the C term across all variables.
y = -108x³ + 45x² + 6x - 3
we can verify our solution using a plotting calculator.
A+b=-3, a=-3-b
ab=-35, and using a from above we get:
(-3-b)b=-35
-3b-b^2=-35
b^2+3b-35=0
b≈-7.6033 and 4.6033
So the two numbers are approximately -7.6033 and 4.6033
#2 is 35°C (just plug in 95 to the formula)
#3:
in the left column are:
(8x-(6+y))
(3/4)w+x^2
in the right column are:
y^2-0.5w
w/4+3(x+y)
to solve you just plug in to the formula
