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kirza4 [7]
3 years ago
11

Today's high temperature is 72°F. If yesterday's high temperature was 87°F, what was the change in high temperatures

Mathematics
1 answer:
Crazy boy [7]3 years ago
7 0

Answer:

15 degrees Fahrenheit

Step-by-step explanation:

Subtract the temperatures

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Write an explanation for both Part A and Part B using 3-4 complete sentences. Part A: Explain how you can determine if a system
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Step-by-step explanation:

Part A : when comparing graphs : A system of equations will have no solutions (on a graph) when your lines never cross each other. They never cross each other because your lines are parallel.

Part B : by comparing each algebraic equation : A system of equations will have no solution if your lines are parallel. Parallel lines will have the same slope but different y intercepts. Example :

2x - y = 2

4x - 2y = 8

put both equations in slope intercept form

y = 2x - 2

y = 2x - 4

they both have the same slope of 2.....and the y intercepts are different....meaning they are parallel lines and have no solutions

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What is the probability of drawing a spade each time a card is drawn from a deck of 52 cards 3 times, if replacement occurs each
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3 years ago
A turtle lives in a garden and a hedgehog lives in the woods. They leave their homes at the same time walk toward each other and
Jlenok [28]

Based on the calculations, the distance between the garden and the woods is equal to 383 meters.

<h3>How to calculate the distance.</h3>

First of all, we would assign a variable to the different speeds of the turtle and hedgehog as follows:

  • Let the turtle's speed be S₁.
  • Let the hedgehog's speed be S₂.

Mathematically, distance is given by this formula:

Distance = speed × time

Translating the word problem into an algebraic expression, we have;

If they both meet in 5 hours:

D = (S₁ + S₂) × 5  

D = 5S₁ + 5S₂      ......equation 1.

Turtle's speed is 10 meters per hour slower than the hedgehog:

S₁ = S₂ - 10    .....equation 2.

If the turtle had left home 4.5 hours earlier than the hedgehog had left his home:

9.5S₁ + 5S₂ = D + 150    .....equation 3.

Substituting enq. 2 into eqn. 1, we have:

D = 5(S₂ - 10) + 5S₂

D = 5S₂ - 50 + 5S₂

D = 10S₂ - 50      .....equation 4.

Equating eqn. 3 and eqn. 4, we have:

10S₂ - 50 = 9.5(S₂ - 10) + 5S₂ - 150

10S₂ - 50 = 9.5S₂ - 95 + 5S₂ - 150

10S₂ - 50 = 14.5S₂ - 245

14.5S₂ - 10S₂ = 245 - 50

4.5S₂ = 195

S₂ = 195/4.5

S₂ = 43.3 m/h.

Now, we can find the distnace:

D = 10S₂ - 50

D = 10(43.3) - 50

D = 433 - 50

D = 383 meters.

Learn more about distance here: brainly.com/question/10545161

4 0
2 years ago
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