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How many eighth graders chose History as their favorite subject. Round answer to the nearest whole number.

Elenna [48]

The percentage of eighth-graders that chose History as their favorite subject is 19%

<h3>Percentages and proportion</h3>

From the given table, we have the following parameters

Total students in the 8th grade = 124 students

Total number of 8th graders that chose history = 11 + 12

Total number of 8th graders that chose history = 23

Required percentage = 23/124 * 100

Required percentage = 19%

Hence the percentage of eighth-graders that chose History as their favorite subject is 19%

Learn more on percentages here: brainly.com/question/24304697

4 0

2 years ago

Nate has $50 to spend at the grocery store. he fills his shopping cart with items totaling $46. At checkout he will have to pay

Akimi4 [234]

Answer:

yes he can

Step-by-step explanation:

he has to pay total is : 46+46x6%=48.76$

so he can pay that

8 0

3 years ago

Read 2 more answers

Given the matrices: 1 2 A= 1 -1 2 1 1 B= 3 4 Calculate AB: C11 C12 [2.1] х 1 2 3 4 C21 C22 C11 = C12 = -2 C22 - C215 DONE

eduard

Answer:

$\:c_{11}=-2,\:\:\:c_{12}=-2$

$\:c_{21}=5,\:\:\:c_{22}=8$

Step-by-step explanation:

Given the matrices

$A=\begin{pmatrix}1&-1\\ 2&1\end{pmatrix}$

$B=\begin{pmatrix}1&2\\ \:3&4\end{pmatrix}$

Calculating AB:

$\begin{pmatrix}1&-1\\ \:\:2&1\end{pmatrix}\times \:\begin{pmatrix}1&2\\ \:\:3&4\end{pmatrix}=\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}$

Multiply the rows of the first matrix by the columns of the second matrix

$=\begin{pmatrix}1\cdot \:1+\left(-1\right)\cdot \:3&1\cdot \:2+\left(-1\right)\cdot \:4\\ 2\cdot \:1+1\cdot \:3&2\cdot \:2+1\cdot \:4\end{pmatrix}$

$=\begin{pmatrix}-2&-2\\ 5&8\end{pmatrix}$

Hence,

$\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}=\begin{pmatrix}-2&-2\\ \:5&8\end{pmatrix}$

Therefore,

$\:c_{11}=-2,\:\:\:c_{12}=-2$

$\:c_{21}=5,\:\:\:c_{22}=8$

5 0

2 years ago

Read 2 more answers

The function d(s) = 0.0056s squared + 0.14s models the stopping distance

victus00 [196]

Answer:

The car must have a speed of 25 kilometres per hour to stop after moving 7 metres.

Step-by-step explanation:

Let be $d(s) = 0.0056\cdot s^{2} + 0.14\cdot s$ , where $d$ is the stopping distance measured in metres and $s$ is the speed measured in kilometres per hour. The second-order polynomial is drawn with the help of a graphing tool and whose outcome is presented below as attachment.

The procedure to find the speed related to the given stopping distance is described below:

1) Construct the graph of $d(s)$ .

2) Add the function $d = 7\,m$ .

3) The point of intersection between both curves contains the speed related to given stopping distance.

In consequence, the car must have a speed of 25 kilometres per hour to stop after moving 7 metres.

4 0

2 years ago

5x+3<7+7x<br> Please explain in clear details

trasher [3.6K]

Answer:

5x just means 5 times so, 5 times a number(or variable)plus three is less than 7 times a number variable)plus 7

4 0

3 years ago