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NeTakaya
3 years ago
10

How many moles of Li3N will be created using 0.24 moles of Li in the given reaction? 6Li + N2 2Li3N 0.04 moles 0.08 moles 0.12 m

oles 0.48 moles 0.72 moles
Chemistry
1 answer:
Damm [24]3 years ago
4 0
6 Li + N2 = 2 Li3N

6 moles Li ------------ 2 moles Li3N
0.24 moles Li ------- moles Li3N

moles Li3N = 0.24 *2 / 6

moles Li3N = 0.48 / 6 => 0.08 moles

Answer B
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2d

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2 years ago
How many milligrams of product can be produced from the complete Diels-Alder reaction of 180. mg of anthracene and 100. mg of ma
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The reaction is already balanced, which means to produce 1 mol of C18H12O3 is necessary 1 mol of anthracene and 1 mol of maleic anhydride.

1 mol of C14H10 equals 178,23 g. As it is used 180 mg of that reagent, we have 0,001 mol of anthracene. With it, the reaction produces 0,001 mol of C18H12O3.

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