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Dahasolnce [82]
3 years ago
12

PLEASE HELP! IN DESPERATE NEED! THX! Please SHOW YOUR WORK! Thx so much! :)

Mathematics
2 answers:
iren2701 [21]3 years ago
7 0
X - 25
------- = 9
  20

x - 25 = 9*20 = 180

x = 180 + 25 = 205  answer
Rom4ik [11]3 years ago
6 0
X equals 45for the second page and the first one would be x = 10
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Answer:

1+1=2

2+2=4

4+3=7

7+4=11

so the patter is number + natural numbers (serially)

Step-by-step explanation:

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Assume that adults were randomly selected for a poll. They were asked if they "favor or oppose using federal tax dollars to fund
ser-zykov [4K]

<u>Testing the hypothesis</u>, it is found that since the <u>p-value of the test is 0.0042 < 0.01</u>, it can be concluded that the proportion of subjects who respond in favor is different of 0.5.

At the null hypothesis, it is tested if the <u>proportion is of 0.5</u>, that is:

H_0: p = 0.5

At the alternative hypothesis, it is tested if the <u>proportion is different of 0.5</u>, that is:

H_1: p \neq 0.5

The test statistic is given by:

z = \frac{\overline{p} - p}{\sqrt{\frac{p(1 - p)}{n}}}

In which:

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  • p is the value tested at the null hypothesis.
  • n is the sample size.

In this problem, the parameters are given by:

p = 0.5, n = 483 + 398 = 881, \overline{p} = \frac{483}{881} = 0.5482

The value of the test statistic is:

z = \frac{\overline{p} - p}{\sqrt{\frac{p(1 - p)}{n}}}

z = \frac{0.5482 - 0.5}{\sqrt{\frac{0.5(0.5)}{881}}}

z = 2.86

Since we have a <u>two-tailed test</u>(test if the proportion is different of a value), the p-value of the test is P(|z| > 2.86), which is 2 multiplied by the p-value of z = -2.86.

Looking at the z-table, z = -2.86 has a p-value of 0.0021.

2(0.0021) = 0.0042

Since the <u>p-value of the test is 0.0042 < 0.01</u>, it can be concluded that the proportion of subjects who respond in favor is different of 0.5.

A similar problem is given at brainly.com/question/24330815

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3 years ago
David bought a poster for an art project. The poster is 2.7 ft wide and 3.9 ft tall. What is the area of the poster? Enter your
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10.53 ft is the Area. :D:D
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