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Dahasolnce [82]
3 years ago
12

PLEASE HELP! IN DESPERATE NEED! THX! Please SHOW YOUR WORK! Thx so much! :)

Mathematics
2 answers:
iren2701 [21]3 years ago
7 0
X - 25
------- = 9
  20

x - 25 = 9*20 = 180

x = 180 + 25 = 205  answer
Rom4ik [11]3 years ago
6 0
X equals 45for the second page and the first one would be x = 10
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Investigate the patern “13/1 family” of fractions. Use plenty of space to show what you find.
Naya [18.7K]

Answer:

2/1 of a family

Step-by-step explanation:

5 0
3 years ago
Aaron used links to create a chain 28.9 cm long.Each link is 1.7 cm long.How many links are in the chain?
dusya [7]
You are given the length of the chain equal to 28.9cm. For each link, the length is 1.7cm long. You are required to find how many links are there in the chain. You just divide 28.9 cm by 1.7 cm to get the answer. The solution is,  
<span>
Number of links = chain length/link  length</span>
Number of links = (28.9cm)/(1.7cm)
<span>Number of links = chain length/link  length</span>
Number of links = 17  
<span><u><span>There are 17 links in a 28.9cm chain length.</span></u><u /></span>
3 0
3 years ago
Read 2 more answers
Describe the behavior of the function ppp around its vertical asymptote at x=-2x=−2x, equals, minus, 2. ​
insens350 [35]

Answer:

x->-2^{-}, p(x)->-\infty and as x->-2^{+}, p(x)->-\infty

Step-by-step explanation:

Given

p(x) = \frac{x^2-2x-3}{x+2} -- Missing from the question

Required

The behavior of the function around its vertical asymptote at x = -2

p(x) = \frac{x^2-2x-3}{x+2}

Expand the numerator

p(x) = \frac{x^2 + x -3x - 3}{x+2}

Factorize

p(x) = \frac{x(x + 1) -3(x + 1)}{x+2}

Factor out x + 1

p(x) = \frac{(x -3)(x + 1)}{x+2}

We test the function using values close to -2 (one value will be less than -2 while the other will be greater than -2)

We are only interested in the sign of the result

----------------------------------------------------------------------------------------------------------

As x approaches -2 implies that:

x -> -2^{-} Say x = -3

p(x) = \frac{(x -3)(x + 1)}{x+2}

p(-3) = \frac{(-3-3)(-3+1)}{-3+2} = \frac{-6 * -2}{-1} = \frac{+12}{-1} = -12

We have a negative value (-12); This will be called negative infinity

This implies that as x approaches -2, p(x) approaches negative infinity

x->-2^{-}, p(x)->-\infty

Take note of the superscript of 2 (this implies that, we approach 2 from a value less than 2)

As x leaves -2 implies that: x>-2

Say x = -2.1

p(-2.1) = \frac{(-2.1-3)(-2.1+1)}{-2.1+2} = \frac{-5.1 * -1.1}{-0.1} = \frac{+5.61}{-0.1} = -56.1

We have a negative value (-56.1); This will be called negative infinity

This implies that as x leaves -2, p(x) approaches negative infinity

x->-2^{+}, p(x)->-\infty

So, the behavior is:

x->-2^{-}, p(x)->-\infty and as x->-2^{+}, p(x)->-\infty

6 0
3 years ago
Help please !!!!!!! thanks, will give brainliest
ludmilkaskok [199]

The correct answer is D. I've had that question before


8 0
3 years ago
2 x 12 divided by (2 + 6) +2^3
TEA [102]

Answer:

11

Step-by-step explanation:

To add fractions, find the LCD and then combine or Pemdas

5 0
3 years ago
Read 2 more answers
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