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Tpy6a [65]
4 years ago
6

0.6239 as a fraction.

Mathematics
2 answers:
Stolb23 [73]4 years ago
6 0
The answer is 6239/10000


Masja [62]4 years ago
5 0

Answer:

The answer is 6239 / 10000

Step-by-step explanation:

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(6p-6/p)•((9p^2)/2p-2)
Alekssandra [29.7K]

Answer:

27p4-27p2-12p+12/p

Step-by-step explanation:

3 0
3 years ago
Dexter has 83 tiles left over from tiling his bathroom floor and he would like to use them to tile the front entrance of his hou
creativ13 [48]

Answer: [0, 396]

Step-by-step explanation:

The domain is the acceptable values of x in the function.  In this case, x = t, the number of tiles.  If you think about it, the minimum number of tiles is 0 (you can't have a negative number of tiles), and the maximum number of tiles is 44 (you only have 44 tiles).  So, the domain for this function is from 0 to 44.

0 to 44 written in interval notation is [0,44].

The range is the acceptable values of y in the function.  In this case, y = A, the area given.  A(t) = 9t, so you can use the acceptable values of t to get the range.  Again, the minimum area is 0 because you can't have negative area. To find the maximum area, plug in the maximum number of tiles: 9.

A(t) = 9t

A = 9(44)

A = 396

With the maximum number of tiles, 44, the area you get is 396 cm².  Therefore, the acceptable values of A are from 0 to 396.

0 to 396 written in interval notation is [0, 396].

4 0
3 years ago
What is all the names for a in the expression 7ab + 3
shepuryov [24]

Answer:

b,d,f are the answers......

5 0
4 years ago
Please help???????????
vagabundo [1.1K]

Answer:

x - \sqrt{7}

Step-by-step explanation:

A polynomial has the form

first term is the term of highest degree followed by term of second etc.

note that x = x^{1} ← degree 1

x - \sqrt{7}

fits this description and is a polynomial of degree 1



5 0
3 years ago
Which is the product of 7/9 and 6?
OLEGan [10]

Answer:

14/3

Step-by-step explanation:

<u>7</u>       x          <u> 6</u>

9                    1

7x6=42

9X1=9

42/9     or 14/3

3 0
3 years ago
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