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charle [14.2K]
4 years ago
7

Write the quadratic equation whose roots are -3 and 3 and whose leading coefficient is 5. (Use the letter x to represent the var

iable)
Mathematics
1 answer:
Bumek [7]4 years ago
4 0
A(x - x₁)(x - x₂) = 0
a=5,  x₁=-3,  x₂ = 3

so:
5(x-(-3))(x-3)=0
5(x+3)(x-3)=0
5(x²-9) = 0
5x² - 45 = 0   ←  answer
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Find the value of x in similar polygons below
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Choice A

Step-by-step explanation:

When you have two shapes that are similar their sides are always proportional. So all we have to do is set up a proportion.

\frac{18}{4.5}=\frac{x}{1.5}

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Answer:

The volume of the irregular figure would be 144 cm^3.

Step-by-step explanation:

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Find the linear approximation of the function g(x) = 3 root 1 + x at a = 0. g(x). Use it to approximate the numbers 3 root 0.95
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Answer:

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\sqrt[3]{0.95} \approx 0.9833

\sqrt[3]{1.1} \approx 1.0333

Step-by-step explanation:

Given the function: g(x)=\sqrt[3]{1+x}

We are to determine the linear approximation of the function g(x) at a = 0.

Linear Approximating Polynomial,L(x)=f(a)+f'(a)(x-a)

a=0

g(0)=\sqrt[3]{1+0}=1

g'(x)=\frac{1}{3}(1+x)^{-2/3} \\g'(0)=\frac{1}{3}(1+0)^{-2/3}=\frac{1}{3}

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L(x)=1+\frac{1}{3}(x-0)\\\\$The linear approximating polynomial of g(x) is:$\\\\L(x)=1+\dfrac{1}{3}x

(b)\sqrt[3]{0.95}= \sqrt[3]{1-0.05}

When x = - 0.05

L(-0.05)=1+\dfrac{1}{3}(-0.05)=0.9833

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(c)

(b)\sqrt[3]{1.1}= \sqrt[3]{1+0.1}

When x = 0.1

L(1.1)=1+\dfrac{1}{3}(0.1)=1.0333

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