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In-s [12.5K]
3 years ago
8

Which polynomial is factored completely

Mathematics
2 answers:
Pani-rosa [81]3 years ago
6 0
a.\ 4(4x^4-1)=4[(2x^2)^2-1^2]=4(2x^2-1)(2x^2+1)-NOT\\\\b.\ 2x(y^3-4y^2+5y)=2xy(y^2-4y+5)-NOT\\\\c.\ 3x(9x^2+1)-YES\\\\d.\ 5x^2-17x+14=5x^2-10x-7x+14\\=5x(x-2)-7(x-2)=(x-2)(5x-7)-NOT
Answer: c.

Ket [755]3 years ago
4 0

Answer: The correct option is c.

Explanation:

Reason for correct option:

3x(9x^2+1)

This expression cannot be factored further because (9x^2+1) is the complete factor. Therefore the option c is correct.

Reason for incorrect option:

5x^2-17x+14=5x^2-10x-7x+14=5x(x-2)-7(x-2)=(x-2)(5x-7)

Since the given expression can be factored further therefore the option d is incorrect.

4(4x^4-1)=4((2x)^2-1)=4(2x^2-1)(2x^2+1)

Since the given expression can be factored further. Therefore the option a is incorrect.

2x(y^3-4y^2+5y)=2xy(y^2-4y+5)

Since the given expression can be factored further. Therefore the option b is incorrect.

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