For the first one, you did good. I will just suggest a couple things.
Statement Reason
JK ≅ LM Given
<JKM ≅ < LMK Given (You did both of these steps so well done.)
MK ≅ MK Reflexive Property (Your angle pair is congruent but isn't one of the interior angle of the triangles you are trying to prove.)
ΔJMK ≅ ΔLKM SAS
Problem 2: (You also have a lot of great stuff here.)
Statement Reason
DE ║ FG Given
DE ≅ FG Given
<DEF≅<FGH Given
<EDF≅<GFH Corresponding Angles (You don't need to know that F is the midpoint but you got corresponding angle pair which is correct.)
ΔEDF≅ΔGFH ASA
<DFE≅<FHG CPCTC
Answer:
There is no solution
Step-by-step explanation:
To solve this first find the area of each of the white shapes inside the rectangle
The formula for the area of a circle is:
A = πr²
In this case we know that the radius is 2
Plug what you know into the area of a circle formula:
A = π2²
A = π4
A = 4π
A ≈ 12.57
The formula for the area of a square is:
A = Length x Height
In this case we know that both length and height are 3
Plug what you know into the formula for area of a square:
A = 3 x 3
A = 9
To find the area of the UNSHADED region simply add together the area of the circle (12.57) with the area of the square (9):
12.57 + 9 ≈ 21.57
To find the area of the SHADED region find the total area of the surrounding rectangle then subtract the area of unshaded area from the total area of the surrounding rectangle.
The formula for the area of a rectangle is:
A = Length x Height
The length is 10 and the height is 7
A = 10 x 7
A = 70
Shaded region:
70 - 21.57 = 48.43
Unshaded region: 21.57
Total area of surrounding rectangle: 70
Shaded region: 48.43
Hope this helped!
~Just a girl in love with Shawn Mendes
The answer is A ratio table.
