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dimulka [17.4K]
4 years ago
13

Which equation is not a linear function? y = x2 y = x + 2 y = 2x y = x - 2

Mathematics
2 answers:
Montano1993 [528]4 years ago
4 0
Y=x2 is not a linear function cause x supposed to be at the end of the number
fgiga [73]4 years ago
3 0
Y= x2 is not linear it is a parabola. There is you me answer hope it helps
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Describe julius caesar as a child
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Answer:

You dare challenge me...

Step-by-step explanation:

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8 0
3 years ago
Isaac has piece of rope that is 5 yards long.Into how many 1/2 yard pieces of rope can Isaac cut the rope
RideAnS [48]
5 divided by 1/2 equal to 10 becuase you need to find how many 1/2 rope can you get from 5
5 0
4 years ago
Find domain of y=rad20-6x
Evgesh-ka [11]
Domain, on an "even root" context, means, an even root cannot have a negative radicand, since  say for example \bf \sqrt{-25}\ne -5\qquad why?\implies (-5)(-5)=25

so... you end up with an "imaginary value"

so... for the case of 20-6x
"x", the domain, or INPUT
can afford to have any value, so long it doesn't make the radicand negative

to check for that, let us make the expression to 0, and see what is "x" then

\bf 20-6x=0\implies 20=6x\implies \cfrac{20}{6}=x\implies \cfrac{10}{3}=x

now, if "x" is 10/3, let's see \bf \sqrt{20-6\left( \frac{10}{3} \right)}\implies \sqrt{20-20}\implies \sqrt{0}\implies 0

now, 0 is not negative, so the radicand is golden

BUT, if "x" has a value higher than 10/3, the radicand turns negative
for example  \bf x=\frac{11}{3}
\\\\\\

\sqrt{20-6\left( \frac{11}{3} \right)}\implies \sqrt{20-22}\implies \sqrt{-2}

so.. that's not a good value for "x"

thus, the domain, or values "x" can safely take on, are all real numbers from 10/3 onwards, or to infinity if you wish
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4 years ago
All real numbers greater thab or equal to 67
sineoko [7]
An equation for that would be.

x => 67
5 0
3 years ago
What is the value of the expression 145÷27?
kondaur [170]

Answer:

5.37037037

Hope this helps!! (:

4 0
3 years ago
Read 2 more answers
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