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Fantom [35]
3 years ago
6

The sum of three consecutive integers is 300. Find the Integers.

Mathematics
1 answer:
IrinaVladis [17]3 years ago
3 0

Answer:

99+100+101

Step-by-step explanation:

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(-2x-5)=23 solve for it step by step please
expeople1 [14]

Answer: x=-14

Step-by-step explanation:

Get rid of parentheses: -2x-5-23=0

Add all the numbers together, and all the variables: -2x-28=0

Move all terms containing x to the left, all other terms to the right:

-2x=28

x=28/-2

x=-14

7 0
3 years ago
Read 2 more answers
Long division<br> 3x+1/6x^6+5x^5+2x^4-9x^3+7x^2-10x+2
inna [77]
(6 x^{6}+5x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2) / (3x+1)

We divide first number from first parenthesis with first number from second parenthesis. Then the resulting number we multiply by all numbers in second parenthesis and substract from first parenthesis.

6 x^{6}/3x = 2 x^{5} \\  \\ 6 x^{6}+5x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2 - 6 x^{6} -2 x^{5} = 3x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2\\

We repeat previous steps until we run out of numbers:
3x^{5}/3x=x^{4} \\ \\ 3x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2-3x^{5}-x^{4}= \\ \\ x^{4}-9x^{3}+7x^{2}-10x+2 \\ \\ \\ x^{4}/3x= \frac{1}{3} x^{3} \\ \\ x^{4}-9x^{3}+7x^{2}-10x+2-x^{4}- \frac{1}{3} x^{3}= \\ \\ - \frac{28}{3} x^{3}+7x^{2}-10x+2 \\ \\ \\ - \frac{28}{3} x^{3}/3x= - \frac{28}{9} x^{2} \\ \\ - \frac{28}{3} x^{3}+7x^{2}-10x+2+ \frac{28}{3} x^{3}+ \frac{28}{9} x^{2} = \\ \\ \frac{91}{9} x^{2}-10x+2
\frac{91}{9} x^{2}/3x=\frac{91}{27} x \\ \\ \frac{91}{9} x^{2}-10x+2-\frac{91}{9} x^{2}-\frac{91}{27} x= \\ \\ -\frac{361}{27} x+2 \\ \\ \\ -\frac{361}{27} x/3x=-\frac{361}{81} \\ \\ -\frac{361}{27} x+2+\frac{361}{27}x+\frac{361}{27}= \\ \\ \frac{415}{27}

We are left with a number that has no x inside. This is remainder.
The final solution is sum of all these solutions and remainder:
(2 x^{5}+x^{4}+\frac{1}{3} x^{3} - \frac{28}{9} x^{2} +\frac{91}{27} x)+(-\frac{361}{81} )
6 0
3 years ago
Solve 5x 2 - 7x + 2 = 0 by completing the square. What are the solutions?
Alexeev081 [22]

Answer:

x=\frac{2}{5} or x=1

Step-by-step explanation:

The given quadratic equation is

5x^2-7x+2=0

Group the constant terms on the right hand side.

5x^2-7x=0-2

5x^2-7x=-2

Divide through by 5.

x^2-\frac{7}{5}x=-\frac{2}{5}

Add the square of half the coefficient of x., which is (\frac{1}{2}\times- \frac{7}{5})^2=\frac{49}{100} to both sides of the equation.

x^2-\frac{7}{5}x+\frac{49}{100}=-\frac{2}{5}+\frac{49}{100}

The left hand side is now a perfect square.

(x-\frac{7}{10})^2=\frac{9}{100}

Take the square root of both sides;

(x-\frac{7}{10})=\pm \sqrt{\frac{9}{100}}

x-\frac{7}{10}=\pm \frac{3}{10}

x=\frac{7}{10}\pm \frac{3}{10}

x=\frac{7-3}{10} or x=\frac{7+3}{10}

x=\frac{4}{10} or x=\frac{10}{10}

x=1 or x=\frac{2}{5}

5 0
3 years ago
Read 2 more answers
The domain of a quadratic function is all real numbers and the range is y s 2. How many x-intercepts does the
mel-nik [20]

Answer:

There are two x-intercepts.

A quadratic function whose maximum degree two. Therefore, Total two x-intercept possible.

We are given the range of quadratic function y less than equal to 2. It means parabola is downward whose maximum value 2.

Here y is greater than 2 and parabola form downward. Here must be two x-intercept.

If a>0 then form open up parabola.

If a<0 then open down parabola.

Here open down parabola. So, we get total two x-intercept.

Please see the attachment for diagram.

5 0
3 years ago
How i can prove the proofs?
Marianna [84]
You can prove the proofs by showing your work to prove the proofs.
3 0
3 years ago
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