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2 years ago

If c=1/3 and b=3 solve 3c divided by (2b to the 2nd power

Mathematics

1 answer:

valentina_108 [34]2 years ago

3 0

Answer:

4 1/2

Step-by-step explanation:

3(1/3) divided by 2(3)2nd power

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professor190 [17]

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Answer:

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Step-by-step explanation:

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3 years ago

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PilotLPTM [1.2K]

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Step-by-step explanation:

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3 years ago

39 is what percent of 156

Romashka-Z-Leto [24]

39 is 25% of 156.
Work: 156 x 0.25 = 39 which means that 25% of 156 is 39.

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2 years ago

For the matrices below. Find all (real) eigenvalues. <br><br> A= [7 9]<br> [0 9]

Jet001 [13]

Answer:

The answer is "9 and 7".

Step-by-step explanation:

Given:

$A=\left[\begin{array}{cc}7&9\\0&9\end{array}\right]$

Using formula:

$|A-\lambda \cdot I|= 0\\\\$

$\to |\left[\begin{array}{cc}7&9\\0&9\end{array}\right]-\lambda \left[\begin{array}{cc}1&0\\0&1\end{array}\right] |=0\\\\\\ \to |\left[\begin{array}{cc}7&9\\0&9\end{array}\right]- \left[\begin{array}{cc}\lambda&0\\0&\lambda\end{array}\right] |=0\\\\\\\to|\left[\begin{array}{cc}7-\lambda &9\\0&9-\lambda\end{array}\right]|=0\\\\\\\to|(7-\lambda)(9-\lambda)|=0\\\\\to (7-\lambda)(9-\lambda)=0\\\\\to 7-\lambda=0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 9-\lambda=0\\\\$

$\to \lambda=7 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \lambda=9\\\\$

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3 years ago