3 years ago

Only need the last one on the bottom please

Mathematics

1 answer:

olga_2 [115]3 years ago

6 0

Lm and jk because corresponding angles theorem

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575 394 9550 bFzN0S come study with me!

Molodets [167]

Answer:

need points

Step-by-step explanation:

gchfyfyjfuf

5 0

2 years ago

The position equation for a particle is s of t equals the square root of the quantity t cubed plus 1 where s is measured in feet

vladimir1956 [14]

$\bf s(t)=\sqrt{t^3+1}
\\\\\\
\cfrac{ds}{dt}=\cfrac{1}{2}(t^3+1)^{-\frac{1}{2}}\cdot 3t^2\implies \boxed{\cfrac{ds}{dt}=\cfrac{3t^2}{2\sqrt{t^3+1}}}\leftarrow v(t)
\\\\\\
\cfrac{d^2s}{dt^2}=\cfrac{6t(2\sqrt{t^3+1})-3t^2\left( \frac{3t^2}{\sqrt{t^3+1}} \right)}{(2\sqrt{t^3+1})^2}\implies 
\cfrac{d^2s}{dt^2}=\cfrac{ \frac{6t(2\sqrt{t^3+1})-1}{\sqrt{t^3+1}} }{4(t^3+1)}$

$\bf \cfrac{d^2s}{dt^2}=\cfrac{6t[2(t^3+1)]-1}{4(t^3+1)\sqrt{t^3+1}}\implies 
\boxed{\cfrac{d^2s}{dt^2}=\cfrac{12t^4+12t-1}{4t^3+4\sqrt{t^3+1}}}\leftarrow a(t)\\\\
-------------------------------\\\\a(2)=\cfrac{215~ft^2}{44~sec}$

8 0

3 years ago

Read 2 more answers

It takes a person 50 minutes to get to campus. He spends t minutes walking to the bus stop and the rest of the time riding the b

amid [387]

Answer:

16.2

Step-by-step explanation:

cause. ur a noob at math

8 0

3 years ago

Find g(x) where g(x) is the translation 3 units right of f(x)=x^2

Fed [463]

Answer:

g(x) = x^2 -6x +9

Step-by-step explanation:

A function f(x) translated right h units and up k units will become ...

g(x) = f(x -h) +k

You want the function f(x) = x^2 to be translated right h=3 units, so it will become ...

g(x) = f(x -3) = (x -3)^2

g(x) = x^2 -6x +9

6 0

2 years ago

#1 Show if the triangles below are similar or not Please help thankyou!!

Tanzania [10]

Answer:

No the triangle are not same because the outer length of triangle is not same

3 0

2 years ago