Answer:
5(x-3)(x+2)=0
Step-by-step explanation:
5x^2-30x=5
5x^2-30x-5=0
5(x^2-6x-1)=0
5(x-3)(x+2)=0
Ok,
The total is 63$:
= 63
It shows us one of the numbers for the equation, 13
+ 13 = 63
Two passes together plus the thirteen equals the total of 63$
the price of the pass is unknown, so we can use a variable to figure it out:
2x + 13 = 63
Now we solve
First subtract 13 from both sides:
2x + 13 - 13 = 63 - 13
Then divide both sides by 2:
2x ÷ 2 = 50 ÷ 2
Now we get our answer:
x = 25
No, they're not equivalent....... i suggest a calculator for this kind of math, just divide the first number by the last and compare them, like this 36/4=9, 56/7=8
the first one is $9 per hat, and the second one is $8 per hat
Step-by-step explanation:
3r + (9 + 2r + 1)
this can be simplified :
3r + (9 + 2r + 1) = 3r + 2r + 9 + 1 = 5r + 10
Answer:
The nonzero value of c will be:
Step-by-step explanation:
Given the function
as
so
switching the sides
subtract c from both sides
Using the zero factor principle
so, the solutions to the quadratic equations are:
Therefore, a nonzero value of c will be:
