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NeTakaya
3 years ago
5

What are the last 2 digits of 7 to the power of 2018. This question was on a past exam paper.

Mathematics
1 answer:
Xelga [282]3 years ago
6 0

Answer:

49

Step-by-step explanation:

  • Try finding pattern of last two digits of 7 to the power of some numbers.

7^1=07

7^2=49

7^3=343

7^4= 2301

7^5= 16807

  • so , the pattern is, 07,49,43,01
  • so, if we start writing all numbers from 1 to 2018 , four number in each line, 2018 will fall in the second column.
  • so it will have 49 as the  last 2 digits [by seeing this pattern : 07,49,43,01 ]
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Step-by-step explanation:

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