If we translate the word problems to mathematical equation,
2x + 3y = 60
The second equation is,
P = xy³
From the first equation, we get the value of y in terms of x.
y = (60 - 2x) / 3
Then, substitute the expression of y to the second equation,
P = x (60-2x) / 3
P = (60x - 2x²) / 3 = 20x - 2x²/3
We derive the equation and equate the derivative to zero.
dP/dx = 0 = 20 - 4x/3
The value of x from the equation is 15.
Hence, the value of x for the value of the second expression to be maximum is equal to 15.
Answer:
it would be both 2
Step-by-step explanation:
2
Solution:
1) Simplify \frac{1}{6}x to \frac{x}{6}
y=\frac{x}{6}-2
2) Add 2 to both sides
y+2=\frac{x}{6}
3) Multiply both sides by 6
(y+2)\times 6=x
4) Regroup terms
6(y+2)=x
5) Switch sides
x=6(y+2)
Done!
Answer:
-6
Step-by-step explanation:
The equation is y = -7x - 6.
The initial value is found when x = 0.
y = -7(0) - 6
y = 0 - 6
y = -6
