Ask question

Ask question

All categories

3 years ago

10

A leaking bucket is filled to 3/4 capacity. After some time, 1/2 of the water has leaked out. What fraction of the water leaked

out of the bucket?
A. 1/4
B. 2/3
C. 3/8
D. 3/16

PLEASE HEELPP ITS URGENT

1 answer:

Ilia_Sergeevich [38]3 years ago

3 0

C. 3/8 is the answer

You might be interested in

Hello! Can someone pls help me???

qwelly [4]

Answer:

5x+6y=60

Step-by-step explanation:

x= $5 per pound of second type of seed

y=$6 per pound of first types of seed

3 0

3 years ago

Newton’s law of universal gravitation, F=Gm1m2/r²,measures the force of gravity between two masses m1 and m2,where r is the dist

Pavel [41]

Answer:

$G=\frac{Fr^2}{m_1m_2}$

Step-by-step explanation:

Since our equation is $F=\frac{Gm_1m_2}{r^2}$ and we want to solve for G, first we divide both sides by the product $m_1m_2$ , which gives:

$\frac{F}{m_1m_2}=\frac{Gm_1m_2}{m_1m_2r^2}=\frac{G}{r^2}$

So we are left with:

$\frac{F}{m_1m_2}=\frac{G}{r^2}$

Now we multiply both sides by $r^2$ , which gives:

$\frac{Fr^2}{m_1m_2}=\frac{Gr^2}{r^2}=G$

Which gives us our final formula:

$G=\frac{Fr^2}{m_1m_2}$

6 0

3 years ago

Solve the system of linear equations<br><br> x + y = 4 and 2x + 3y = 0

forsale [732]

solve this answer by using substitution. set the first equation to x=-y+4 then substitute -y+4 for x in the second equation.

2(-y+4) + 3y=0

-2y+8 + 3y=0

y+8=0

y=-8

now use -8 and solve for x

x+(-8)=4

x=12

8 0

3 years ago

Bill went to the museum at 11:30 A.M . He stayed for 3 1/2 hours.When did he leave ?

tatuchka [14]

To start, note that an hour is 60 minutes long. A 1/2 hour, or half hour, is then 60/2=30 minutes. Therefore, when we have 11 hours and 30 minutes, we have 11 and a half hours. Adding 3 and a half to that, we get 11.5+3.5=15 (a half can also be expressed as .5, although it's not typically done that way when expressing time - it just might be easier to visualize it this way). Therefore, we are 15 hours into the day. However, we can't just stop there - we have to account for AM and PM. Therefore, we subtract 12 hours from 15. If the number is positive, we are in PM - otherwise, we're in AM. Therefore, as 15-12=3, the time is in PM. The remaining number is the time, so Bill leaves at 3 PM. If we are left with a decimal (e.g. 3.25), we would keep the 3 and multiply the 0.25 (the decimal) by 60 to figure out how many minutes we have, so 3.25 would turn into 3+0.25*60=3:15.

Feel free to ask further questions!

5 0

3 years ago

PLS HELP ME!!! The figure is made up of a cone and a hemisphere. To the nearest whole number, what is the approximate volume of

Pachacha [2.7K]

Hello!

The figure is made up of a cone and a hemisphere. To the nearest whole number, what is the approximate volume of this figure? Use 3.14 to approximate π . Enter your answer in the box. cm³

Data: (Cone)

h (height) = 12 cm

r (radius) = 4 cm (The diameter is 8 being twice the radius)

Adopting: $\pi \approx 3.14$

V (volume) = ?

Solving: (Cone volume)

$V = \dfrac{ \pi *r^2*h}{3}$

$V = \dfrac{ 3.14 *4^2*\diagup\!\!\!\!\!12^4}{\diagup\!\!\!\!3}$

$V = 3.14*16*4$

$\boxed{V = 200.96\:cm^3}$

Note: Now, let's find the volume of a hemisphere.

Data: (hemisphere volume)

V (volume) = ?

r (radius) = 4 cm

Adopting: $\pi \approx 3.14$

If: We know that the volume of a sphere is $V = 4* \pi * \dfrac{r^3}{3}$ , but we have a hemisphere, so the formula will be half the volume of the hemisphere $V = \dfrac{1}{2}* 4* \pi * \dfrac{r^3}{3} \to \boxed{V = 2* \pi * \dfrac{r^3}{3}}$

Formula: (Volume of the hemisphere)

$V = 2* \pi * \dfrac{r^3}{3}$

Solving:

$V = 2* \pi * \dfrac{r^3}{3}$

$V = 2*3.14 * \dfrac{4^3}{3}$

$V = 2*3.14 * \dfrac{64}{3}$

$V = \dfrac{401.92}{3}$

$\boxed{ V_{hemisphere} \approx 133.97\:cm^3}$

What is the approximate volume of this figure?

Now, to find the total volume of the figure, add the values: (cone volume + hemisphere volume)

Volume of the figure = cone volume + hemisphere volume

Volume of the figure = 200.96 cm³ + 133.97 cm³

$\boxed{\boxed{\boxed{V = 334.93\:cm^3 \to Volume\:of\:the\:figure \approx 335\:cm^3 }}}\end{array}}\qquad\quad\checkmark$

Answer:

The volume of the figure is approximately 335 cm³

_______________________

I Hope this helps, greetings ... Dexteright02! =)

8 0

3 years ago

Read 2 more answers