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3 years ago

HELP ASSAPP WITH THIS QUESTION PLEASE

Mathematics

2 answers:

Fudgin [204]3 years ago

7 0

50° angle hope this helps!
I'm not the best a lot math so if I got it wrong I apologise

34kurt3 years ago

4 0

The measurement of <ABC is 50 degrees

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PLEASE HELP ME I AM TAKING A TEST AND I NEED HELP!!!

zhannawk [14.2K]

Part A.
y=4x+3

Part B.
11=4x+3
8=4x
2=x
2 dollars

Part C.
4(3)+4(2)=12+8=20

It would be enough if there is no sales tax.

Hope this helps!
Your fortune is "Only one fortune a day!"

3 0

3 years ago

Given that f(x) = x2 - 16 and g(x) = 20 - x, find (f-g)-4),

zavuch27 [327]

$( {x}^{2} - 16) - (20 - x) - 4 \\ = {x}^{2} + x - 40$

4 0

2 years ago

Which best represents the center of the data set below ? mean median range mode

enyata [817]

Answer:{}

B. Median

Their is no real explanation.

7 0

3 years ago

Read 2 more answers

What is the x-coordinate of the solution of the system? x+y+3 4x-y=-38

steposvetlana [31]

Note: I am assuming the first equation is:

x+y = 3

Answer:

The solution to the system of equations is:

(x, y) = (-2, 36)

Therefore, the x-coordinate of the solution of the system

x = -2

Step-by-step explanation:

Given the system of equations

$\begin{bmatrix}x+y=34\\ x-y=-38\end{bmatrix}$

subtracting the equations

$x-y=-38$

$-$

$\underline{x+y=34}$

$-2y=-72$

solve -2y for y

$-2y=-72$

Divide both sides by -2

$\frac{-2y}{-2}=\frac{-72}{-2}$

$y=36$

For x+y=34 plug in y = 36

$x+36=34$

Subtract 36 from both sides

$x+36-36=34-36$

Simplify

$x=-2$

Thus, the solution to the system of equations is:

(x, y) = (-2, 36)

Therefore, the x-coordinate of the solution of the system

x = -2

6 0

3 years ago

What is the center of the hyperbola whose equation is (y+3)^2/81-(x-6)^2/89=1?

xxMikexx [17]

We have been given an equation of hyperbola $\frac{(y+3)^2}{81}-\frac{(x-6)^2}{89}=1$ . We are asked to find the center of hyperbola.

We know that standard equation of a vertical hyperbola is in form $\frac{(y-k)^2}{b^2}-\frac{(x-h)^2}{a^2}=1$ , where point (h,k) represents center of hyperbola.

Upon comparing our given equation with standard vertical hyperbola, we can see that the value of h is 6.

To find the value of k, we need to rewrite our equation as:

$\frac{(y-(-3))^2}{81}-\frac{(x-6)^2}{89}=1$

Now we can see that value of k is $-3$ . Therefore, the vertex of given hyperbola will be at point $(6,-3)$ and option D is the correct choice.

6 0

3 years ago