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Degger [83]
3 years ago
10

PLS HELP ! Will give brainliest

Mathematics
1 answer:
Darina [25.2K]3 years ago
3 0

Answer:

Step-by-step explanation:

The quadratic formula would be the following...

x = \frac{-b (+-)\sqrt{b^{2} - 4ac } }{2a}

where the original quadratic equation would be represented as follows

ax^{2} + bx +c = 0

Using this information and the information provided in the image we can plug in the quadratic equation values in the image to form the quadratic formula.

\frac{-(-20)±\sqrt{(-20)^{2} - 4(16)(-6) } }{2(16)}

That would be the correct order for the values.

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32 is closer to 33 than it is to 40
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Write an equation in slope-intercept form for each of these representations.
PtichkaEL [24]

Answer:

1.     y= -1/4x +2

2.    y= -2x -1

Step-by-step explanation:

7 0
3 years ago
A) What is the slope and the y-intercept of the equation?
Zielflug [23.3K]

Answer:

see explanation

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + b ( m is the slope and b the y- intercept )

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (0, 3) and (x₂, y₂ ) = (4, 0) ← 2 points on the line

m = \frac{0-3}{4-0} = \frac{-3}{4} = - \frac{3}{4}

The y- intercept is where the line crosses the y- axis

The line crosses the y- axis at (0, 3 ) ⇒ b = 3

(b)

y = - \frac{3}{4} x + 3 ← equation of line

8 0
3 years ago
124.4 divided by 4, idk they want more characters even tho it’s REALLY SIMPLE
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Step-by-step explanation:

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The graph below describes the journey of a train between two cities.
Veseljchak [2.6K]

Answer:

[A] Acceleration in first 15 min = 200  km/h²

[B] Distance between two cities = 125 km

[C] Average Speed of journey =  62.5  km/hr

Step-by-step explanation:

To Solve:

Acceleration in first 15 min

Distance between two cities  

Average speed of journey

Solve:

[A] Work out the acceleration, in km/h?, in the first 15 mins.

Each horizontal block is 1/8 hr = 7.5 min

Each vertical block is 10 km/hr

Time                     Velocity  km/hr

0 Min  ( 0 hr)            0

15 Min (1/4 hr)           50

45 Min (3/4 hr)         50

60 MIn  ( 1 hr)            100

90 Min  ( 3/2 hr)        100

120 Min ( 2hr)            0

Acceleration in first 15 min  (1/4 hr)  =  (50 - 0)/(1/4 - 0)  = 50/(1/4)

= 200  km/h²

Hence, Answer for [A] = 200  km/h²

[B] Work out the distance between the two cities. $60 Velocity (in km/h)

= (1/2)(0 + 50)(1/4 - 0)  + 50 * (3/4 - 1/4)  + (1/2)(50 + 100)(1 - 3/4)  + 100 * (3/2 - 1) + (1/2)(100 + 0)(2 - 3/2)

=  25/4  + 25 + 75/4   + 50 + 25

= 125

Distance between two cities = 125 km

[C] Work out the average speed of the train during 20 the journey.

Average Speed of journey = 125/2  = 62.5  km/hr

[RevyBreeze]

5 0
2 years ago
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