The answer is
bus topology.
Although considered obsolete nowadays, it is the simplest
and cheapest network topology to install and modify as only one main cable is
required for installation. It is also well suited for temporary and small
networks with a few nodes.
Answer:
SLE = AV * EF, is the correct answer for the above question. Where SLE refers the "Single loss expectancy", AV refers to the "asset value" and EF refers to the "exposure factor".
Explanation:
- Risk management is used to identify the risk in any project. When the project is going to develop then there is a need to identify the risk which comes under the development of the project.
- The above-defined formula is related to risk management which concludes about the asset risk in any project.
- The asset is a term that can be called for the physical or logical resources of the organization.
Answer:Less time invested in planning the network,
The use for fewer outlets, expansion in number of uplink ports
Explanation: A fixed-configuration switch is switch with a constant number of ports which can not be expanded.
Modular switches are switches whose number of ports can be expanded. Modular switches allows port expansion which gives it an advantage over fixed-configuration switch,with modular switches you spend less time in planning your work due to the availability of more ports needed to connect devices.
Modular switches doesn't require more power outlets unlike fixed-configuration switch where you need to connect different device on different power outlets.
Answer:
allow for easy transferability of documents from one person to another
Explanation:
Collaboration tools are used to support a group of two or more individuals to accomplish a common goal or objective. They help people to work together as these tools open door for communication between the people involved. Transferring of documents from one person to another is made possible by web-based collaboration tools.
Answer:
Speed of child = 8.94 m/s
Explanation:
Given:
Mass of child = 25 kg
Height = 4 meter
Find:
Speed of child
Computation:
P.E = mgh
P.E = (25)(10)(4)
P.E = 1000 J
K.E = P.E
So,
(1/2)(m)(v)² = 1000
(1/2)(25)(v)² = 1000
(v)² = 80
v = 8.94 m/s
Speed of child = 8.94 m/s