Four-pair UTP uses ________ connectors a)snap b)ST or SC c)None of these

Consider a set of mobile computing clients in a certain town who each

poizon [28]

Answer: answer given in the explanation

Explanation:

We have n clients and k-base stations, say each client has to be connected to a base station that is located at a distance say 'r'. now the base stations doesn't have allocation for more than L clients.

To begin, let us produce a network which consists of edges and vertex

Network (N) = (V,E)

where V = [S, cl-l, - - - - cl-n, bs-l - - - - - - bs-k, t]

given that cl-l, - - - - - cl-n represents nodes for the clients

also we have that bs-l, - - - - - bs-k represents the nodes for base station

Also

E = [ (s, cl-i), (cl-i,bs-j), (bs-j,t)]

(s, cl-i) = have capacity for all cl-i (clients)

(cl-i,bs-j) = have capacity for all cl-i clients & bs-j (stations)

⇒ using Fond Fulkorson algorithm we find the max flow in N

⇒ connecting cl-i clients to bs-j stations

like (cl-i, bs-j) = 1

if f(cl-i, bs-j) = 0

⇒ say any connection were to produce a valid flow, then

if cl-i (clients) connected f(s,cl-i) = 1 (o otherwise)

if cl-i (clients) connected to bs-j(stations) f(cl-i,bs-j) = 1 (o otherwise)

f(bs-j,t) = no of clients (cl-i) connected to bs-j

⇒ on each node, the max flow value (f) is longer than the no of clients that can be connected.

⇒ create the connection between the client and base station i.e. cl-l to base bs-j iff f(cl-i, bs-j) = 1

⇒ when considering the capacity, we see that any client cannot directly connect to the base stations, and also the base stations cannot handle more than L clients, that is because the load allocated to the base statsion is L.

from this, we say f is the max no of clients (cl-i) that can be connected if we find the max flow, we can thus connect the client to the base stations easily.

cheers i hope this helps

5 0

3 years ago

1| def saveUserProfile(firstName, lastName, age, height, country):

Feliz [49]

Answer:

Joyner

David

USA

1.8

30

Explanation:

def saveUserProfile(firstName, lastName, age, height, country):

This is the definition of function named saveUserProfile which accepts the following parameters:

firstName
lastName
age
height
country

filename = lastName + firstName + ".txt"

When the file is created it will be named as the lastName and firstName string combined with .txt as extension. For example if the lastName contains the name string Joyner and firstName contains the name David then the file created to be written is named as JoynerDavid.txt

outputFile = open(filename, "w")

This statement uses open() method in write mode and uses outputFile object to access the file. "w" represents write mode i.e. file is opened in write mode to write on it.

a) Joyner is written on line 1 of that file because of the following statement of above function:

print(lastName, file = outputFile)

This statement prints the string stored in lastName i.e. Joyner. Here outputFile opens the file in "w" write mode and writes the last name to the first line of the file.

b) David is written on line 2 of that file because of the following statement of above function:

print(firstName, file = outputFile)

This statement prints the string stored in firstName i.e. David. Here outputFile opens the file in "w" write mode and writes the first name to the second line of the file.

c) USA is written on line 3 of that file because of the following statement of above function:

print(country, file = outputFile)

This statement prints the data stored in country i.e. USA. Here outputFile opens the file in "w" write mode and writes the country name to the third line of the file.

d) 1.8 is written on line 4 of that file because of the following statement of above function:

print(height, file = outputFile)

This statement prints the value stored in height i.e. 1.8. Here outputFile opens the file in "w" write mode and writes the height value to the fourth line of the file.

e) 30 is written on line 5 of that file because of the following statement of above function:

print(age, file = outputFile)

This statement prints the value stored in age parameter of function saveUserProfile i.e. 30. Here outputFile opens the file in "w" write mode and writes the age value to the fifth line of the file.

7 0

3 years ago

write a C++ program that ask the user for the number of cookies eaten and display the calorie consumption

Artyom0805 [142]

Answer:

#include <iostream>

using namespace std;

int main()

{

int cookies;

cin >> cookies;

cout << "The calorie consumption is: " << cookies * 142 << endl;

return 0;

}

Explanation:

First line: include basic library of C++(input and output).

using namespace std;

Says to compiler we are using std.

int main() Main function

int cookies, cookies variable, of int type

cin >> cookies

get the number of the cookies from user

cout Print the text and calories(one cookie have 142 calories)

Have a nice day ;)

4 0

3 years ago

What happens when you double-click one of the graphic options in the middle panel of the choose a smartart graphic dialog box?

pickupchik [31]

When you open MS Word, selecting the insert option and clicking SmartArt, will pop up SmartArt dialog box. Double-clicking on one of the graphic options in the middle panel will automatically select and place the graphic art you want. It is an easy way of inserting a SmartArt of your choice without selecting the art itself and clicking OK.

3 0

3 years ago

Read 2 more answers

Write a method called findNames that meets the following specs: It takes two arguments: a list of strings, allNames, and a strin

Anna11 [10]

Answer:

public class Solution {

public static void main(String args[]) {

String[] allNames = new String[]{"Bob Smith", "Elroy Jetson", "Christina Johnson", "Rachael Baker", "cHRis", "Chris Conly"};

String searchString = "cHRis";

findNames(allNames, searchString);

}

public static void findNames(String[] listOfName, String nameToFind){

ArrayList<String> resultName = new ArrayList<String>();

for(String name : listOfName){

if (name.toLowerCase().contains(nameToFind.toLowerCase())){

resultName.add(name);

}

for(String result : resultName){

System.out.println(result);

}

Explanation:

The class was created called Solution. The second line define the main function. Inside the main function; we initialized and assign an array called allNames to hold the list of all name. Then a String called searchString was also defined. The searchString is the string to search for in each element of allNames array. The two variables (allNames and searchString) are passed as argument to the findNames method when it is called.

The method findNames is defined and it accept two parameters, an array containing list of names and the name to search for.

Inside the findNames method, we initialized and assigned an ArrayList called resultName. The resultName variable is to hold list of element found that contain the searchString.

The first for-loop goes through the elements in the allNames array and compare it with the searchString. If any element is found containing the searchString; it is added to the resultName variable.

The second for-loop goes through the elements of the resultName array and output it. The output is empty if no element was found added to the resultName variable.

During comparison, the both string were converted to lower case before the comparison because same lowercase character does not equal same uppercase character. For instance 'A' is not same as 'a'.

8 0

3 years ago