All categories

3 years ago

What is the value of x? Look at image attached

Mathematics

1 answer:

Veronika [31]3 years ago

5 0

half of the sum of the given angles.

36+60 = 96

96/2 = 48

x = 48 degrees

You might be interested in

7. Patrick tosses a penny and a number cube, with faces numbered 1 through 6, at the

lions [1.4K]

Answer:

B. 1/3 or 33.3%

Step-by-step explanation:

H- 1 ,2 ,3, 4, 5, 6

T- 1, 2, 3, 4, 5, 6

Multiples of 3: 3, 6, 9, 12, etc..

2/6 simplified is 1/3

So, the probability that the penny will land on heads and the number cube will land on a multiple of 3, is 1/3 or 33.3%

7 0

3 years ago

Can anyone solve this:

ludmilkaskok [199]

So fuctions mean
if
f(x)=x+2 then if you put in 3 for x then
f(3)=3+2=5 so

if x=years after 2000
in 2020 then
2020-2000=20 so x=20
subsitute
f(20)=9204e^0.022(20)

e could be:
1. common base of logarithms (memorised to 15 decmals) 2.718281828459045
2. a computer notation exg if you have 3e11 that means 3 times 10^11

if it is 1
9240 times (2.718281828459045^(0.022 times 20))=( simplify exponent first) 9240 times (2.718281828459045^0.44)=9204 times 1.5527072185113=14291.1 or rounded to 14291

if it is 2
9204 times 10^(0.022 times 20)=9204 times 10^(0.44)=9204 times 254.491 rounded to 254

so the answer dependes on what e represents,

if e is:
1. common base of logarithms (memorised to 15 decmals) 2.718281828459045, then answer is 14291

2. a computer notation exg if you have 3e11 that means 3 times 10^11 =254

7 0

3 years ago

Read 2 more answers

Two consecutive even integers have a sum of 45

sleet_krkn [62]

22 + 23 = 45 those are consecutive numbers that equal 45.
20 + 25 = 45 those are even although not necessarily consecutive back-to-back.

8 0

3 years ago

Why is finding the sum in math so important?

sveticcg [70]

A sum in math is the answer after you have Added 2 numbers.

I’m not sure why this would be specifically important.

6 0

3 years ago

Please add am explanation.

iren2701 [21]

Answer:

5(k + 1) and 5k + 5

Step-by-step explanation:

The easiest way to do this is to pick any number to substitute in for the variable k for ALL of the expressions, and find the expressions that equal the same as the first expression being compared.

For example, lets just make k equal 1 to make things easy. Plug 1 into k into the first expression. 2k + 2 + k + 3 + 2k → 2(1) + 2 + (1) + 3 + 2(1) = 10.

Now we do the same to the rest of the expressions and see which ones ALSO equal 10.

5(k + 1) → 5(1 + 1) = 10

5k + 5 → 5(1) + 5 = 10

5 + k^5 → 5 + (1)^5 = 6

5k^5 → 5(1)^5 = 5

5 0

2 years ago