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never [62]
4 years ago
5

How to find the zeros of a non factorable function?

Mathematics
1 answer:
Mice21 [21]4 years ago
5 0
Assuming it's for a polynomial function, this video explains a lot https://www.youtube.com/watch?v=OrLz7yide2g hope this helps:)
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Which pairs are like terms in the expression below? Select all that apply.
koban [17]

Answer:

B.  and E.

Step-by-step explanation:

hope it helps ;)

4 0
3 years ago
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Molly painted a line around the entire perimeter of the basketball court. The length of the court was 32 meters and the width wa
Citrus2011 [14]
First, we need to find the perimeter of the basketball court. To find the perimeter, you need to add all the sides of the shape, or in this case add the width(2) and height(2).

(32 x 2) + (17x2) = 64 + 34 = 98

the perimeter is 98 meters.

She drew a line around the perimeter, and the perimeter is 98 meters, so the line si also more or less 98 meters.

The correct answer is D.
8 0
3 years ago
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If cos⁡ x=−45, and 180° < x < 270°, what is tan⁡(2x)?
iVinArrow [24]

Tan2x =\frac{-24}{7}

<u>Step-by-step explanation:</u>

Here we have , cos x = -4/5 ( corrected as given -45 which is not possible ) ,

180° < x < 270° i.e. in third quadrant  . We need to find tan⁡(2x) . Let's find out:

⇒ Tan\alpha  = \frac{sin\alpha }{cos\alpha }

⇒ Tan\alpha  = \frac{\sqrt{1-(cos\alpha)^2} }{cos\alpha }

⇒ Tan\alpha  = \frac{\sqrt{1-(\frac{-4}{5})^2} }{\frac{-4}{5} }

⇒ Tan\alpha  = \frac{-5}{4}\sqrt{1-(\frac{16}{25}) }

⇒ Tan\alpha  = \frac{-5}{4}\sqrt{(\frac{25-16}{25}) }

⇒ Tan\alpha  = \frac{-5}{4}(\frac{3}{5}) }

⇒ Tan\alpha  = \frac{-3}{4} , since in third quadrant . Tan\alpha  = \frac{-3}{4} remains same .

Now , Tan2x = \frac{2tanx}{1-(tanx)^{2}}}

⇒ Tan2x = \frac{2tanx}{1-(tanx)^{2}}}

⇒ Tan2x = \frac{2(\frac{-3}{4})}{1-(\frac{-3}{4})^{2}}}

⇒ Tan2x = \frac{-3}{2}(\frac{16}{7})

⇒ Tan2x =\frac{-24}{7}

Therefore, Tan2x =\frac{-24}{7} .

5 0
4 years ago
What is the equation of the graph below ​
Delicious77 [7]

Answer:

y = csc (x) + 2

Step-by-step explanation:

From the graph, we can derive the parent function y = csc(x). Notice how there are asymptotes at x = 2πk and x = π + 2πk, which is where csc(x) is undefined.

Finally, we can see a vertical shift of 2 which we can see from the mid-line of the graph which is at y = 3.

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3 years ago
Andrew is evaluating his current financial position by totaling his monthly cash inflows and outflows. His cash inflows each mon
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15 dollars left each month
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