Answer:
6cm
Step-by-step explanation:



= 6
The linear relationship which exists between the change in weight and number of days of hibernation in a hedgedog can be modeled using the equation y = - 0.03 + 0
- Change in weight per day of hibernation = - 0.03
- Change in weight for 115 days = - 3.45 ounces
A linear model can be created using the data in the table given using a regression calculator or excel ;
The linear model obtained in the form y = m + bx is :
- y = - 0.03x + 0
- y = change in weight
- x = number of days of hibernation
- Intercept = 0
- Slope = -0.03
- The slope value of the function gives the change in weight value per number of days of hibernation ; which is -0.03.
- Using the regression equation, substitute, the vlaue of x = 115
- -0.03(115) + 0 = - 3.45
Therefore, the change in weight after 115 days of hibernation is - 3.45 ounces.
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V(t) = dy/dt = 40 - 32t
ai). average velocity = (v(0.5) - v(0))/(0.5 - 0) = ((40 - 32(0.5)) - (40 - 32(0)))/0.5 = (40 - 16 - 40)/0.5 = -16/0.5 = -32m / s
ii). average velocity = (v(0.1) - v(0))/(0.1 - 0) = ((40 - 32(0.1)) - (40 - 32(0)))/0.1 = (40 - 3.2 - 40)/0.1 = -3.2/0.1 = -32m / s
iii). average velocity = (v(0.05) - v(0))/(0.05 - 0) = ((40 - 32(0.05)) - (40 - 32(0)))/0.05 = (40 - 1.6 - 40)/0.05 = -1.6/0.05 = -32m / s