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faltersainse [42]
3 years ago
8

X+Y=100 4.5X+20Y=822 Elimination, graphing,and substitution methods.

Mathematics
1 answer:
serious [3.7K]3 years ago
4 0

Answer:

y=10

4 SX +20 Y= 822

Elimination

X - 10 -4

UX - 822-20Y

6.5

10 -4 = 822-201

45

- 4.5 = 822 - 204

15.54=774

4 = 90:13

= -40.129

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A book store is having a 30% off sale. Diary of a wimpy kid books are now $6.30 each. What was the original price of the books?
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6.30x0.3= 1.89

6.30+1.89=8.19
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3 years ago
A triangle has an area of 38.4 cm2. The
lisov135 [29]

Answer:

6cm

Step-by-step explanation:

A = \frac{h_b b}{2}

38.4 = \frac{12.8_b b}{2}

b = 2\frac{A}{h_b}

b = 2\frac{38.4}{12.8} = 6

8 0
2 years ago
A house has decreased in value by 26% since purchased if its current value is 185,00 what was its value when it was purchased
Elodia [21]
The answer is 23,310 because it’s right
6 0
2 years ago
The table shows the relationship
Airida [17]

The linear relationship which exists between the change in weight and number of days of hibernation in a hedgedog can be modeled using the equation y = - 0.03 + 0

  • Change in weight per day of hibernation = - 0.03
  • Change in weight for 115 days = - 3.45 ounces

A linear model can be created using the data in the table given using a regression calculator or excel ;

The linear model obtained in the form y = m + bx is :

  • y = - 0.03x + 0
  • y = change in weight
  • x = number of days of hibernation
  • Intercept = 0
  • Slope = -0.03

  • The slope value of the function gives the change in weight value per number of days of hibernation ; which is -0.03.

  • Using the regression equation, substitute, the vlaue of x = 115
  • -0.03(115) + 0 = - 3.45

Therefore, the change in weight after 115 days of hibernation is - 3.45 ounces.

Learn more :brainly.com/question/18405415

8 0
1 year ago
a ball is thrown into the air with a velocity of 40 ft/s, its height in feet seconds later is given by y=40t-16t^2. a) Find the
Scorpion4ik [409]
V(t) = dy/dt = 40 - 32t
ai). average velocity = (v(0.5) - v(0))/(0.5 - 0) = ((40 - 32(0.5)) - (40 - 32(0)))/0.5 = (40 - 16 - 40)/0.5 = -16/0.5 = -32m / s

ii). average velocity = (v(0.1) - v(0))/(0.1 - 0) = ((40 - 32(0.1)) - (40 - 32(0)))/0.1 = (40 - 3.2 - 40)/0.1 = -3.2/0.1 = -32m / s

iii). average velocity = (v(0.05) - v(0))/(0.05 - 0) = ((40 - 32(0.05)) - (40 - 32(0)))/0.05 = (40 - 1.6 - 40)/0.05 = -1.6/0.05 = -32m / s
5 0
3 years ago
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