From a reference point at the beginning of the track, Ward's car will be located 4s+8 feet down the track after s seconds. That is, it starts 8 feet down the track, and increases its distance by 4 feet every second.

From the same reference point, Heskey's car will be located 6s feet down the track after s seconds. Its distance starts from zero and is increasing at the rate of 6 feet every second.

For Heskey's distance to exceed Ward's distance you want ...

6s > 4s +8 . . . . . . matches choice F

6 0

3 years ago

Derive the equation of the parabola with a focus at (_5, 5) and a directrix of y = -1.

mars1129 [50]

Answer: Option D is correct.

Step-by-step explanation:

Since we have given that

focus = (-5,5)

and a directrix y= -1

Since, equation of parabola in this case will be

$(x-h)^2=4.a(y-k)$

Now, here

$y=k-a=-1\\\\\text { focus =(h,k+a)}\\\\\text{So,} k+a=5\\\\\text{ by solving these two equation , we get }\\\\a=3\text{ and } k=2$

So equation will be

$(x+5)^2=4\times 3(y-2)\\\\(x+5)^2=12(y-3)\\\\y=\frac{1}{12}(x+5)^2+2$

So, option D is correct .

4 0

2 years ago

Read 2 more answers

What is the slope intercept form of the graph

Bingel [31]

Answer:

y = x + 1

Step-by-step explanation:

y = mx + b

First, find the y-intercept. This is where the line intersects with the y-axis.

So, 1. -> y = mx + 1

Next, find the slope. For every 1/2 moving to the right, it also vertically increased by 1/2.

(1/2)/(1/2)

= 1 -> y = x + 1

Therefore, y = x + 1

7 0

2 years ago

Help meee please <br><img src="https://tex.z-dn.net/?f=%20%20%5Csqrt%7B%3F%7D%20%7B78%7D%20%7D%20" id="TexFormula1" title=" \sq

tekilochka [14]

I think it is 8.83? I am not positive but it is worth a try

7 0

2 years ago