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3 years ago

Please help me with this question on algebra

Mathematics

1 answer:

grandymaker [24]3 years ago

4 0

The solution is option D.

0     4
- 6     1
3    -4

Rember rows times columns.

=>
a11 = 4*0 + 0*(-3) = 0

a12 = 4*1 + 0*1 = 4 + 0 = 4

a21 = -1*0 + 2*(-3) = 0 - 6 = -6

a22 = -1*1 + 2*1 = -1 + 2 = 1

a31 = -3*0 + (-1)*(-3) = 0 + 3 = 3

a32 = -3*1 + (-1)*1 = -3 - 1 = -4

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For a medical study, a researcher wishes to select people in the middle 60% of the population based on blood pressure.

Finger [1]

Answer:

Lower limit: 113.28

Upper limit: 126.72

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 120, \sigma = 8$

Middle 60%

So it goes from X when Z has a pvalue of 0.5 - 0.6/2 = 0.2 to X when Z has a pvalue of 0.5 + 0.6/2 = 0.8

Lower limit

X when Z has a pvalue of 0.20. So X when $Z = -0.84$

$Z = \frac{X - \mu}{\sigma}$

$-0.84 = \frac{X - 120}{8}$

$X - 120 = -0.84*8$

$X = 113.28$

Upper limit

X when Z has a pvalue of 0.80. So X when $Z = 0.84$

$Z = \frac{X - \mu}{\sigma}$

$0.84 = \frac{X - 120}{8}$

$X - 120 = 0.84*8$

$X = 126.72$

4 0

3 years ago

In order for you to use the goodnees-of-fit test, the test of independence, or the test of homogeneity, the expected frequencies

nataly862011 [7]

The condition for the expected value in the goodness of fit test is that the expected frequency is at least 5.

According to the statement

we have to find the condition of the expected values in the case of testing of goodness-of-fit test.

So, For this purpose we know that the

The goodness of fit test is of a statistical model describes how well it fits a set of observations. Measures of goodness of fit typically summarize the discrepancy between observed values and the values expected.

So, The main condition of the expected value for the goodness of fit test is

For each category, the expected frequency is at least 5.

Without this condition the test is not possible, so overall this the main condition related the goodness of fit test.

So, The condition for the expected value in the goodness of fit test is that the expected frequency is at least 5.

Learn more about goodness of fit test here

brainly.com/question/17257574

#SPJ1

6 0

1 year ago

I Need Help With Graphing Linear Functions

NNADVOKAT [17]

The answer should be option c