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Aneli [31]
4 years ago
7

Simplify the fraction4/8

Mathematics
1 answer:
TiliK225 [7]4 years ago
8 0
The answer is 1/2 when you simplify it
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A class has average height of 68 inches and a standard division of 2 inches what height do you need to be taller than 90% of the
Y_Kistochka [10]

Answer:

65.426

Step-by-step explanation:

Given that:

Mean height (m) = 68 inches

Standard deviation (s) = 2 inches

Height required to be taller than 90% of the class :

P(Z > x) = 0.9

The corresponding Zscore is - 1.282 (Z probability calculator)

Using the Zscore relation :

Zscore = (x - m) / s

-1.282 = (x - 68) / 2

-1.282 * 2 = x - 68

-2.564 = x - 68

-2.564 + 68 = x

x = 65.436

8 0
3 years ago
What is the solution of the equation (x – 5)^2 + 3(x – 5) + 9 = 0? Use u substitution and the quadratic formula to solve.
xz_007 [3.2K]

Answer:

x = \dfrac{7 \pm 3i\sqrt{3}}{2}

Step-by-step explanation:

(x – 5)^2 + 3(x – 5) + 9 = 0

This is a quadratic equation in x - 5.

Let u = x - 5, then the quadratic equation becomes:

u^2 + 3u + 9 = 0

We can use the quadratic formula to solve for u.

u = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}

u = \dfrac{-3 \pm \sqrt{3^2 - 4(1)(9)}}{2(1)}

u = \dfrac{-3 \pm \sqrt{9 - 36}}{2}

u = \dfrac{-3 \pm \sqrt{-27}}{2}

u = \dfrac{-3 \pm 3i\sqrt{3}}{2}

Since u = x - 5, now we substitute x - 5 for u and solve for x.

x - 5 = \dfrac{-3 \pm 3i\sqrt{3}}{2}

x = \dfrac{-3 \pm 3i\sqrt{3}}{2} + 5

x = \dfrac{-3 \pm 3i\sqrt{3}}{2} + \dfrac{10}{2}

x = \dfrac{7 \pm 3i\sqrt{3}}{2}

7 0
3 years ago
How much water does Janine drink in a day? She normally drinks 6 bottles a day, each 16.9 ounces.
AfilCa [17]

Answer:

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4 0
3 years ago
(f +g)x= g(x)+ f (x)<br><br> Is the this true or false?
Bess [88]

Answer:

True

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Help me on this question please. Thx
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The trapezoid was translated Right 6 ,down 5
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