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Alexxx [7]
3 years ago
6

In 7 hours, Tony reads 42 chapters of a book, What is his rate in chapters per hour?

Mathematics
2 answers:
Sophie [7]3 years ago
8 0

Answer:

6 chapters/hour

Step-by-step explanation:

42/7=6

grin007 [14]3 years ago
5 0

Answer:

He reads about 6 chapters per hour!

<h3>Explanation: </h3>

To solve, divide 42 by 7 to get about how many chapters are read per hour.

42 divided by 7 = 6

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Find the sum of the positive integers less than 200 which are not multiples of 4 and 7​
taurus [48]

Answer:

12942 is the sum of positive integers between 1 (inclusive) and 199 (inclusive) that are not multiples of 4 and not multiples 7.

Step-by-step explanation:

For an arithmetic series with:

  • a_1 as the first term,
  • a_n as the last term, and
  • d as the common difference,

there would be \displaystyle \left(\frac{a_n - a_1}{d} + 1\right) terms, where as the sum would be \displaystyle \frac{1}{2}\, \displaystyle \underbrace{\left(\frac{a_n - a_1}{d} + 1\right)}_\text{number of terms}\, (a_1 + a_n).

Positive integers between 1 (inclusive) and 199 (inclusive) include:

1,\, 2,\, \dots,\, 199.

The common difference of this arithmetic series is 1. There would be (199 - 1) + 1 = 199 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times ((199 - 1) + 1) \times (1 + 199) = 19900 \end{aligned}.

Similarly, positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 4 include:

4,\, 8,\, \dots,\, 196.

The common difference of this arithmetic series is 4. There would be (196 - 4) / 4 + 1 = 49 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 49 \times (4 + 196) = 4900 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 7 include:

7,\, 14,\, \dots,\, 196.

The common difference of this arithmetic series is 7. There would be (196 - 7) / 7 + 1 = 28 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 28 \times (7 + 196) = 2842 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 28 (integers that are both multiples of 4 and multiples of 7) include:

28,\, 56,\, \dots,\, 196.

The common difference of this arithmetic series is 28. There would be (196 - 28) / 28 + 1 = 7 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 7 \times (28 + 196) = 784 \end{aligned}.

The requested sum will be equal to:

  • the sum of all integers from 1 to 199,
  • minus the sum of all integer multiples of 4 between 1\! and 199\!, and the sum integer multiples of 7 between 1 and 199,
  • plus the sum of all integer multiples of 28 between 1 and 199- these numbers were subtracted twice in the previous step and should be added back to the sum once.

That is:

19900 - 4900 - 2842 + 784 = 12942.

8 0
3 years ago
For all functions of the form f(x) = ax2 + bx + c, which is true when b = 0?
Klio2033 [76]
When b=0
f(x)=ax^2+c

test each
A. with x^2-1, A is false
B. with -x^2-1, B is false
C. cannot find contradiction
D. the axis is actually x=0, 0 is nithere positive nor negative, false


answer is C

7 0
3 years ago
Read 2 more answers
There is a decrease in power. It can be concluded that there has also been a change in: A)current or voltage.
Serhud [2]
There is a decrease in power. It can be concluded that there has also been a change in:

A) current or voltage.
5 0
3 years ago
Plsss help meeeee 7^-8 divided by 7^-11
Andrej [43]

Answer:

i think the answer is 7^3

Step-by-step explanation:

when dividing numbers with exponents, you just subtract the smaller exponent from the larger one

pls tell me if im wrong

4 0
3 years ago
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What number can go into 26 and 10?
lesya [120]
10...................
6 0
3 years ago
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