A proton moving along the x axis has an initial velocity of 4.0 × 106 m/s and a constant acceleration of 6.0 × 1012 m/s2. What i
s the velocity of the proton after it has traveled a distance of 80 cm? Group of answer choices
2 answers:
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Answer:
The speed of the block when is fallen 30cm
v=0.726
Explanation:
∑F= (m2)g - ƒ - (m1)g*sin(θ) = (m1)a
g = 9.81 m/s²
ƒ = μN = μ(m1)g
(0.200)(9.81) - (0.1)(0.290)(9.81) - (0.290)(9.81)sin(30°) = (0.290)a
Answer
given,
total charge Q = 100 n C
= 100 × 10⁻⁹ C
radius of the solid sphere = 30 cm
= 0.3 m
Volume of sphere =
=
=0.113 m³
a) volume charge density
ρ = 8.85 × 10⁻⁷ C/m³
b) at r = 10 cm = 0.1 m
charge in the sphere at radius
= 3.7037 \times 10^{-9}C[/tex]
Field strength
=
at r = 20 cm = 0.2 m
=
at r = 30 cm
= 9.99 N/C