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andrey2020 [161]
3 years ago
5

What is 2+2 is 4 - 1 =?? Know your memes!

Physics
2 answers:
lana [24]3 years ago
8 0
Very funny. Can I do all your homework for you?
nasty-shy [4]3 years ago
6 0

Answer:

2+2=4

4-1=3

Explanation:

haha lol

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Immediately after being struck by a hammer, the nail (mass of 50 g) has a velocity of 50 m/s. The total frictional force is 62.5
Marina86 [1]

Answer:

nail will stop after traveling 1000 m    

Explanation:

We have given mass m = 50 gram = 0.05 kg

Frictional force which is used to stop the mass F = 62.5 kN

Initial velocity is given u = 50 m/sec

From newton's law force is equal to F = ma, here m is mass and a is acceleration

So a=\frac{F}{m}=\frac{62.5\times 10^3}{0.05}=1.25\times 10^6m/sec^2

As finally nail stops so final velocity v = 0 m/sec

From third equation of motion v^2=u^2+2as

So 0^2=50^2-2\times 1.25\times 10^6\times s

s = 1000 m

So nail will stop after traveling 1000 m

8 0
3 years ago
Laura and Elana are discussing how to solve the following problem: "A canary sits 10 m from the end of a 30-m-long clothesline,
horrorfan [7]

Answer:

f=2.236\ Hz

Explanation:

Given:

Length of a rope,l=30\ m

Position of Canary on the rope from one end, l_c=10\ m

Position of Grackle on the rope from another end, l_g=5\ m

Tension in the rope, F_T=200\ N

linear mass distribution on the rope, \mu=0.1\ kg.m^{-1}

We have for the speed of wave on the string:

v^2=\frac{F_T}{\mu}

v^2=\frac{200}{\0.1}

v=44.7\ m.s^{-1}

<em>For canary to be undisturbed we need a node at this location.</em>

<em>Also, at the end close to Canary there must be a node to avoid any change in pattern of vibration.</em>

So,

the distance between Canary and the closer end must be equal to half the wavelength.

\frac{\lambda}{2} =10\ m

\Rightarrow \lambda=20\ m

∴Wavelength of wave to be produced = 20 m. This will give us nodes at the multiples of 10 and anti-nodes at the multiples of 5.

Now, frequency:

f=\frac{v}{\lambda}

f=\frac{44.7}{20}

f=2.236\ Hz

3 0
3 years ago
CAN SOMEONE HELP PLEASE
kolbaska11 [484]

Microplastics contain harmful chemicals that can accumulate in the food chain. The other chemicals released into the water when the plastic breaks down also has a negative impact on the sealife around. And with humans consuming contaminated fish and seafood, plastic pollution is certainly a human health issue too. microplastics were providing a medium to facilitate the transport of other toxic compounds such as heavy metals and organic pollutants.

6 0
3 years ago
A t-rated switch may be used to (its/a) ______ current capacity when controlling an incandescent lighting load.
jok3333 [9.3K]

<u>Rated </u>

A t-rated switch may be used to (its/a) <u>Rated</u> current capacity current capacity when controlling an incandescent lighting load.

<h3>What is "current rating"?</h3>
  • The greatest current that a fuse is rated to carry for an infinite duration without significantly degrading the fuse element is known as the current rating.
  • There is also a large selection of power switching transistors that have voltage ratings well over 1000V and current ratings up to several hundred amps.

<h3>What does the term "rated current" mean?</h3>
  • When an electrical device receives its rated voltage and outputs its rated power, it flows at its rated current.
  • So, when a device is designed for a certain amperage, that amperage is referred to as the equipment's rated current.

<h3>What does electrical "rated" mean?</h3>
  • An electrical appliance's rating reveals the voltage range at which it is intended to operate as well as the current consumption at that range.
  • These numbers are typically shown on a rating plate that is fastened to the device, such as 230 volts, 3 amps.

To learn more about current capacity visit:

brainly.com/question/27987428

#SPJ4

6 0
2 years ago
Interactive Solution 9.1 presents a model for solving this problem. The wheel of a car has a radius of 0.380 m. The engine of th
Vilka [71]

Answer:

The magnitude of the static frictional force is 1200 N

Explanation:

given information :

radius, r = 0.380 m

applied-torque, τ1 = 456 N

The car has a constant velocity, thus the acceleration is zero

α = 0

Στ = I α

τ1 - τ2 = I α

τ2 = counter-torque

τ1 - τ2 = 0

τ1 = τ2

r x F_{s} = τ1

F_{s} = the static frictional force (N)

F_{s} = τ1 /r

  = 456 N/0.380 m

  = 1200 N

7 0
3 years ago
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