5.9 × 10^24 = 5,900,000,000,000,000,000,000,000 minus
13,000,000,000,000,000,000,000 equals
5,887,000,000,000,000,000,000,000 kg
which is the amount greater that Earth's mass is. you could write this problem as
5.9 × 10^24 - 13 × 10^21 = 5.887 × 10^21
Answer:
g-1(x) = 3(x + 7).
Domain is All Real values of x.
Range is All Real values of the function.
Step-by-step explanation:
Let y = 1/3 x - 7
1/3 x = y + 7
Multiply both sides by 3:
x = 3(y + 7)
So the inverse of g(x) = g-1(x) = 3(x + 7).
Domain is All Real values of x.
Range is All Real values of the function.
Answer:
Let the present age of the man be x years.
Age of the man 15 years ago =(x−15) years and
Age of the man 15 years later =(x+15) years
According to the given condition, we have
(x+15)=2(x−15)
⇒x+15=2x−30
⇒x−2x=−30−15
⇒−x=−45 or x=45 years
Hence, the present age of the man is 45 years.
Step-by-step explanation:
Hope it helps you..
Your welcome in advance..
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Answer:
12,400
Step-by-step explanation:
so what you are going to first is 400 times 31 which is 12,400
Answer:
3,750 cars.
Step-by-step explanation:
We are given that the equation:
Models the relationsip between <em>y</em>, the number of unfilled seats in the stadium, and <em>x</em>, the number of cars in the parking lot.
We want to determine the number of cars in the parking lot when there are no unfilled seats in the stadium.
When there are no unfilled seats in the stadium, <em>y</em> = 0. Thus:
Solve for <em>x</em>. Subtract 9000 from both sides:
Divide both sides by -2.4:
So, there will be 3,750 cars in the parking lot when there are no unfilled seats in the stadium.
