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3 years ago

Help please hdjdhdhdjdj

Mathematics

2 answers:

GaryK [48]3 years ago

8 0

When you make a graph you would start on the x axis and go over 6.5 and up 2

Charra [1.4K]3 years ago

7 0

Use A Graph

I Hope This Helped!

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Factor the following polynomial completely 6x^5-30x^4-84x^3

Andrei [34K]

Answer:

6x^3(x+2)(x-7)

Step-by-step explanation:

1st step: factor out common term, 6x^3(x^2 - 5x - 14)

2nd step: Factor x^2 - 5x - 14, (x + 2)(x - 7)

3rd step: simplify, 6x^3(x+2)(x-7)

I am joyus to assist :)

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3 years ago

What percent does 5.2 represent? Round your answers to the nearest tenth of a percent.

dezoksy [38]

5.2 as a percent is 520%

3 0

3 years ago

The product of two consecutive numbers is ninety. what are the numbers

Savatey [412]

Answer:

9 and 10

Step-by-step explanation:

8 0

3 years ago

PLEASE HELP I WILL MARK YOU BRAINLIEST

stira [4]

Answer:

1. <u>2448</u> do 612x4

2.she got <u>$23 </u>because he has four children and splits all do 72 divide by 4 and add 5 and thats ur answer

hope this helped

5 0

3 years ago

Read 2 more answers

The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d

jek_recluse [69]

Answer:

50%

Step-by-step explanation:

68-95-99.7 rule

68% of all values lie within the 1 standard deviation from mean $(\mu-\sigma,\mu+\sigma)$

95% of all values lie within the 1 standard deviation from mean $(\mu-1\sigma,\mu+1\sigma)$

99.7% of all values lie within the 1 standard deviation from mean $(\mu-3\sigma,\mu+3\sigma)$

The distribution of the number of daily requests is bell-shaped and has a mean of 55 and a standard deviation of 4.

$\mu = 55\\\sigma = 4$

68% of all values lie within the 1 standard deviation from mean $(\mu-\sigma,\mu+\sigma)$ = $(55-4,55+4)$ = $(51,59)$

95% of all values lie within the 2 standard deviation from mean $(\mu-1\sigma,\mu+1\sigma)$ = $(55-2(4),55+2(4))$ = $(47,63)$

99.7% of all values lie within the 3 standard deviation from mean $(\mu-3\sigma,\mu+3\sigma)$ = $(55-3(4),55+3(4))$ = $(43,67)$

Refer the attached figure

P(43<x<55)=2.5%+13.5%+34%=50%

Hence The approximate percentage of light bulb replacement requests numbering between 43 and 55 is 50%

4 0

3 years ago