Answer:I dont see a image send a image and I will answer
Step-by-step explanation:
Solution
For this case we can do the following:
11y - 3x = 18
16y -3x = 33
We can multiply the first equation by -1 and we got:
-11y +3x =-18
16y -3x = 33
_______________
16y -11y = 33-18
5y = 15
y= 15/5 = 3
And then solving for x we got
x = -(18 -11*3)/ 3= -15/3 = 5
Well the angle is acute at the 3 it would be a right angle so I'm guessing it's 30 degrees but if I'm wrong u could use a protractor to find the angle of degrees
Answer:
3141.59
Step-by-step explanation:
Note: Consider the side of first triangle is TQ instead of TA.
Given:
Triangles TQM and TPN which share vertex T.
To find:
The theorem which shows that 
.
Solution:
In triangle TQM and TPN,
[Given]
[Given]
[Given]
Since two sides and their including angle are congruent in both triangles, therefore both triangles are congruent by SAS postulate.
[SAS]
Therefore, the correct option is C.
