All categories

3 years ago

Help ASAP!! See screenshot below.

Mathematics

1 answer:

Anika [276]3 years ago

5 0

ANSWER

The relation is not a function.

EXPLANATION

The relation is not a function because we have an x-coordinate mapping on to more than one y-coordinate.

This occurs at x=1.

The ordered pairs (1,1) and (1,3) disqualify the relation from being a function.

Hence the relation is not a function.

You might be interested in

A pair of shoes usually sells for $67. If the shoes are 40% off, and sales tax is 8%, what is the total price of the shoes, incl

Gekata [30.6K]

If it is 40% off, it means you have to pay 60% of its price.
$67 × 60/100 = $40.20
the 8% of sales tax is added from the $40.20
$40.20 × 8/100 = $3.22
total price = $40.20 + $3.22 = $43.42

5 0

2 years ago

Sum of cubes: (a b)(a2 – ab b2) = a3 b3 Difference of cubes: (a – b)(a2 ab b2) = a3 – b3 Which products result in a sum or diffe

valentina_108 [34]

By comparing all the options with the formula of sum of cubes and difference of cubes we get that $(x+4)\left(x^{2}-4 x+16\right)$ is sum of cubes

<h3>What is formula of sum of cubes and difference of cubes?</h3>

Formula of sum of cubes and difference of cubes are following

$(a+b)(a^2 -ab +b^2) = a^3+ b^3 \\\\\\(a - b)(a^2+ ab+ b^2) = a^3 - b^3$

(a)

$(x-4) \left(x^{2}+4 x-16\right)\\=(x-4) \left(x^{2}+4 x-4^2\right)\\\\$

by comparison with formula we can say that this is neither sum or nor difference of cubes.

(b)

$(x-1)\left(x^{2}-x+1\right)\\=(x-1)\left(x^{2}-x+1^2\right)$

by comparison with formula we can say that this is neither sum nor difference of cubes.

(c)

$(x+1)(x-1)=x^{2}-1^{2}\\$

we can say that this is neither sum nor difference of cube as it's difference of squares.

(d)

$(x+4)\left(x^{2}-4 x+16\right)\\\\(x+4)\left(x^{2}-4 x+4^2\right)$

by comparison with formula this is equal to

$x^{3}+4^{3}\\$

Hence this is sum of cubes

(e)

$(x+4)\left(x^{2}+4 x+16\right)\\(x+4)\left(x^{2}+4 x+4^2\right)$

by comparison with formula we can say that this is neither sum nor difference of cubes.

By comparing all the options with the formula of sum of cubes and difference of cubes we get that $(x+4)\left(x^{2}-4 x+16\right)$ is sum of cubes

To know more about cubes visit: brainly.com/question/107100

8 0

1 year ago

A 32 year old mother realized that her age is twice the sum of her two children ages. Her son Jose is two years older than her d

jenyasd209 [6]

Again, guess and test should work perfectly fine. Since 2(x+y)=32, x+y = 16. Because y-2 =x, y could be = 9 and x = 7. Hope that help!

3 0

2 years ago

Read 2 more answers

If a is one-factor x, what is the other factor

NARA [144]

B-y is the another factor