Answer:
All of the above
Step-by-step explanation:
Also, this is a history, not a maths problem
The pairs are 1 and 10. 2 and 5.
Answer:

Step-by-step explanation:
We have been given that when a cylindrical tank is filled with water at a rate of 22 cubic meters per hour, the level of water in the tank rises at a rate of 0.7 meters per hour. We are asked to find the approximate radius of tank in meters.
We will use volume of cylinder formula to solve our given problem as:
, where,
r = Radius,
h = Height of cylinder.
Since the level of water in the tank rises at a rate of 0.7 meters per hour, so height of cylinder would be
meters at
.
Upon substituting these values in above formula, we will get:





Now, we will take positive square root of both sides as radius cannot be negative.


Therefore, radius of tank would be approximately square root of 10 m.
Okay so on average if they can go 25 miles per gallon that would mean you could just multiply 25 and 7 to get 175. So on average they could go 175 miles on 7 gallons of gas. Keep in mind that the answer can and will change depending on traffic, how fast or slow they are going, and if they are traveling behind a big-rig that moves more air that would normally be putting pressure on the car to push out of the way but the big-rig helps save gas but it can also waste more gas if they are driving slower then normal.
Sorry for the extra information once I start it's hard to stop. Any way I hope this helps.
Step-by-step explanation:
Hey there!
The 1st equation is;
y= 1/2 x-8.............(i)
Comparing the equation y= mx+c. We get;
Slope (m1) = 1/2
The equation of point which moves through point (-3,-4).
(y-y1) = m2 (x-x1). {Use one-point formula to find out the equation}
(y+4) = m2 (x+3)..………(ii)
Now, we need to find m2.
So, the condition of perpendicular lines: m1*m2= -1.


Therefore, m2 = -2.
So, let's keep value of m2 in eqaution (ii).
y+4 = -2(X+3)
y+4 = -2x-6
y = -2x -10.
Therefore, the eqaution is y= -2x-10.
<em><u>Hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>