3 years ago

Given the function f(x)=3^x, find the value of f^-1(27)

Mathematics

1 answer:

Shalnov [3]3 years ago

7 0

This is asking you to solve the equation ...

... 27 = 3^x

You can use logarithms to find

... log(27) = x·log(3)

... log(27)/log(3) = x = 1.43136376.../0.47712125...

... x = 3

Or, you can use your knowledge of small cubes and match exponents.

... 3^3 = 3^x

... 3 = x

You might be interested in

Line w is steeper than line t and has a y-intercept that is below the y-intercept of line t. Which function could be represented

anzhelika [568]

Answer:

i think the first one not 100% though

3 0

3 years ago

Multiply (−4)(−2)(−5) A. -40 B. -8 C. 8 D. 40

wlad13 [49]

(-4)(-2)= 8
8(-5)= -40
Answer: -40

8 0

3 years ago

What is the equation in slope intercept form for (2,5) (3,12)

kondaur [170]

Slope formula: y2-y1/x2-x1

= 12-5/3-2

= 7/1

= 7

_____

Best Regards,

Wolfyy :)

7 0

3 years ago

Combine Like Terms

Mazyrski [523]

Answer:

-2g-12

Step-by-step explanation:

5 0

2 years ago

Which statement best describes f(x)= -2 √x-7 +1 –6 is in the domain of f(x) but not in the range of f(x). –6 is not in the domai

Archy [21]

Answer:

B. -6 does not belong to the domain but belongs to the range of f(x).

Step-by-step explanation:

We have the function, $f(x)=-2\sqrt{x-7}+1$ .

So, the domain of the function is obtained when $x-7\geq 0$ i.e. $x\geq 7$

That is, the domain is {x | x≥ 7}.

Now as we have,

$x\geq 7$ → $x-7\geq 0$ → $\sqrt{x-7} \geq 0$ → $-2\sqrt{x-7} \leq 0$ → $-2\sqrt{x-7}+1 \leq 1$ .

That is, $f(x)\leq 1$

Thus, the range of the function f(x) is {y | y≤ 1}.

Thus, we can see that,

-6 does not belong to the domain but belongs to the range of f(x).

5 0

3 years ago