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3 years ago

HELP ME . I NEED THE ANSWER NOW PLEASE HELP SMALLER X AND LARGER X

Mathematics

2 answers:

statuscvo [17]3 years ago

5 0

X = 12 that is the answer

s2008m [1.1K]3 years ago

3 0

Answer:

smaller x= -12

larger x= 12

Step-by-step explanation:

$3x^2+4=436\\$

subtract 4

$3x^2=432$

divide by 3

$x^2=144$

square root

$\sqrt{x^2} =\sqrt{144}$

$x= +-\sqrt{144}$

$x= 12\\x= - 12$

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3 years ago

Recall that m(t) = (1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500g sample of phosphorus-32 decays

katrin2010 [14]

The question is incomplete, here is the complete question:

Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.

Answer: The half life of the sample of phosphorus-32 is $14.28days^{-1}$

Step-by-step explanation:

The equation used to calculate the half life of the sample is given as:

$m(t)=m_o(1/2)^{t/h}$

where,

m(t) = amount of sample after time 't' = 356 g

$m_o$ = initial amount of the sample = 500 g

t = time period = 7 days

h = half life of the sample = ?

Putting values in above equation, we get:

$356=500\times (\frac{1}{2})^{7/h}\\\\h=14.28days^{-1}$

Hence, the half life of the sample of phosphorus-32 is $14.28days^{-1}$

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