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ikadub [295]
3 years ago
14

HELP ME . I NEED THE ANSWER NOW PLEASE HELP SMALLER X AND LARGER X

Mathematics
2 answers:
statuscvo [17]3 years ago
5 0
X = 12 that is the answer
s2008m [1.1K]3 years ago
3 0

Answer:

smaller x= -12

larger x= 12

Step-by-step explanation:

3x^2+4=436\\

subtract 4

3x^2=432

divide by 3

x^2=144

square root

\sqrt{x^2} =\sqrt{144}

x= +-\sqrt{144}

x= 12\\x= - 12

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8 0
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Read 2 more answers
Help plz I could really use it
Maru [420]
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8 0
3 years ago
Recall that m(t) = (1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500g sample of phosphorus-32 decays
katrin2010 [14]

The question is incomplete, here is the complete question:

Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.

<u>Answer:</u> The half life of the sample of phosphorus-32 is 14.28days^{-1}

<u>Step-by-step explanation:</u>

The equation used to calculate the half life of the sample is given as:

m(t)=m_o(1/2)^{t/h}

where,

m(t) =  amount of sample after time 't' = 356 g

m_o = initial amount of the sample = 500 g

t = time period = 7 days

h = half life of the sample = ?

Putting values in above equation, we get:

356=500\times (\frac{1}{2})^{7/h}\\\\h=14.28days^{-1}

Hence, the half life of the sample of phosphorus-32 is 14.28days^{-1}

7 0
4 years ago
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