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Alexxx [7]
3 years ago
10

Help my sister step by step show work so she can understand because I forgot how to do this stuff

Mathematics
1 answer:
nikdorinn [45]3 years ago
8 0
The volume of this shape is 960

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What is the value of x-y if x= -1/5 and y=7/15
Vitek1552 [10]
The answer to this problem is -0.66666
6 0
3 years ago
This school is also thinking of changing their mascot to an armadillo. To change mascot, a 55% supermajority is needed. How many
Dennis_Churaev [7]

Answer:

132 students

Step-by-step explanation:

100% means all of something, so 100% can also be written as 1.00

Since we need 55% of 240, we can multiply 240 by 0.55 and get 132.

5 0
3 years ago
4:3 and 25:45 are equal ratios true or false
kondaur [170]
False.

The scale factor for 3 and 45 is 15.

45 / 3 = 15.

We know that 25 isn't even a whole number for the scale factor, because no number x 4 can equal 25 (whole numbers only).

25 / 3 = 6.33333
8 0
3 years ago
QUESTION: WHATS BETTER <br><br> APPLE JUICE OR ORANGE JUICE
alexandr1967 [171]

Answer:

orange juice is better than Apple Juice

5 0
2 years ago
Find the solution of the given initial value problem:<br><br> y''- y = 0, y(0) = 2, y'(0) = -1/2
igor_vitrenko [27]

Answer:  The required solution of the given IVP is

y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.

Step-by-step explanation:  We are given to find the solution of the following initial value problem :

y^{\prime\prime}-y=0,~~~y(0)=2,~~y^\prime(0)=-\dfrac{1}{2}.

Let y=e^{mx} be an auxiliary solution of the given differential equation.

Then, we have

y^\prime=me^{mx},~~~~~y^{\prime\prime}=m^2e^{mx}.

Substituting these values in the given differential equation, we have

m^2e^{mx}-e^{mx}=0\\\\\Rightarrow (m^2-1)e^{mx}=0\\\\\Rightarrow m^2-1=0~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mx}\neq0]\\\\\Rightarrow m^2=1\\\\\Rightarrow m=\pm1.

So, the general solution of the given equation is

y(x)=Ae^x+Be^{-x}, where A and B are constants.

This gives, after differentiating with respect to x that

y^\prime(x)=Ae^x-Be^{-x}.

The given conditions implies that

y(0)=2\\\\\Rightarrow A+B=2~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

and

y^\prime(0)=-\dfrac{1}{2}\\\\\\\Rightarrow A-B=-\dfrac{1}{2}~~~~~~~~~~~~~~~~~~~~~~~~(ii)

Adding equations (i) and (ii), we get

2A=2-\dfrac{1}{2}\\\\\\\Rightarrow 2A=\dfrac{3}{2}\\\\\\\Rightarrow A=\dfrac{3}{4}.

From equation (i), we get

\dfrac{3}{4}+B=2\\\\\\\Rightarrow B=2-\dfrac{3}{4}\\\\\\\Rightarrow B=\dfrac{5}{4}.

Substituting the values of A and B in the general solution, we get

y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.

Thus, the required solution of the given IVP is

y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.

4 0
3 years ago
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